Last visit was: 23 Apr 2024, 15:21 It is currently 23 Apr 2024, 15:21

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
User avatar
Manager
Manager
Joined: 08 Aug 2005
Posts: 216
Own Kudos [?]: 355 [28]
Given Kudos: 0
Send PM
Most Helpful Reply
avatar
Director
Director
Joined: 28 Dec 2005
Posts: 697
Own Kudos [?]: 535 [7]
Given Kudos: 2
Send PM
General Discussion
CEO
CEO
Joined: 29 Jan 2005
Posts: 2887
Own Kudos [?]: 1117 [1]
Given Kudos: 0
Send PM
User avatar
Manager
Manager
Joined: 14 Jun 2007
Posts: 77
Own Kudos [?]: 74 [0]
Given Kudos: 0
Location: Vienna, Austria
Send PM
Re: Division R of Company Q has 1,000 employees. What is the average (arit [#permalink]
cant we just add both averages together and then divide over 2? i know it´s a stupid question but pls guys be so kind and tell me logically why not :-)

thank you
User avatar
Director
Director
Joined: 17 Jun 2008
Posts: 614
Own Kudos [?]: 444 [3]
Given Kudos: 0
Send PM
Re: Division R of Company Q has 1,000 employees. What is the average (arit [#permalink]
3
Kudos
domleon wrote:
cant we just add both averages together and then divide over 2? i know it´s a stupid question but pls guys be so kind and tell me logically why not :-)

thank you


No. That cannot be done. Check the following.

if total employees of division A is x1 and total salary is s1 then average = s1/x1.
If rest of employees is x2 and total salary of these is s2 then average = s2/x2.

Sum of the two averages = (s1/x1) + (s2/x2).

However, average at the company level = (s1+s2)/(x1+x2) and this is not the same as (s1/x1) + (s2/x2).

I hope, this helps.
SVP
SVP
Joined: 17 Nov 2007
Posts: 2408
Own Kudos [?]: 10035 [4]
Given Kudos: 361
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Send PM
Re: Division R of Company Q has 1,000 employees. What is the average (arit [#permalink]
1
Kudos
3
Bookmarks
Expert Reply
We can express the average annual salary of Company Q as:

\(S = \frac{S_r * N_r+ S_{not-r}*N_{not-r}}{N_r+N_{not-r}}\)

where
- \(S_r\) - The average annual salary of the employees in Division R
- \(S_{not-r}\) - The average annual salary of the employees who are not in Division R
- \(N_r\) - The number of employees in Division R
- \(N_{not-r}\) - The number of employees who are not in Division R

So, we don't know the number of employees who are not in Division R.

You can also use huge/tiny numbers to check your answer. If \(N_{not-r}=0\) or only 1 employee, S = 30K or will be very close to 30K. At the same time, if \(N_{not-r}>>1000\), S will be very close to 35K. So we need to know at least \(\frac{N_{not-r}}{N_r}\) ratio.
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32628
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: Division R of Company Q has 1,000 employees. What is the average (arit [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: Division R of Company Q has 1,000 employees. What is the average (arit [#permalink]
Moderator:
Math Expert
92883 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne