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# Does 4 divide (n^2 + 2)?? 1. n is even 2. n is odd

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Does 4 divide (n^2 + 2)?? 1. n is even 2. n is odd [#permalink]

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12 Aug 2004, 18:25
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Does 4 divide (n^2 + 2)??

1. n is even
2. n is odd
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Joined: 15 Dec 2003
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12 Aug 2004, 18:41
D
1) put in any even number for n^2+ 2 and it will never be divisible by 2
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Best Regards,

Paul

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12 Aug 2004, 18:59
Paul wrote:
D
1) put in any even number for n^2+ 2 and it will never be divisible by 2

Wow... I was careless on that one. EEK!
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12 Aug 2004, 20:42
(n^2+2)/4 = (n^2+2)/(2*2). So if (n^2+2)is even, it can divided evenly
by 4.

1. If n is even, n^2+2 = even
2. If n is odd, n^2+2 = even

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13 Aug 2004, 00:44
if n is even (n^2 + 2) will never be divided by 4

n = 2k
(n^2 + 2) = (4k^2 + 2)
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13 Aug 2004, 06:18
Paul, OlegC are u saying that, for "n" being even or odd the expression is NOT divisible and hence the question can be answered by either statements???
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13 Aug 2004, 06:34
cbrf3 wrote:
Paul, OlegC are u saying that, for "n" being even or odd the expression is NOT divisible and hence the question can be answered by either statements???

yes. n, being even or odd, in the given equation, will never be divisible by 4. Only way it is divisible by 4 is if it is not an integer. ie root2, root6, root10 and so on
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Best Regards,

Paul

13 Aug 2004, 06:34
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