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# Does anyone know the answer?

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Intern
Joined: 19 Jul 2007
Posts: 1

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19 Jul 2007, 14:08
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi there guys,

This is a tough GMAT question, any hep will be appreciatble

Each employee on a certain task is either a manager or a director. What percent of the employees on the task force are directors?

1. The average (arithmetic mean) salary of the managers on the task force is 5000 less then the average of all employees on the task force

2. The average (arithmetic mean) salary of the directors on the task force is 15000 greater then the average of all employees on the task force

1. Statement 1 is sufficient
2. Statement 2 is sufficient
3. Both statements are sufficient , but neither alone
4. Each statement is sufficient
5. Statements 1 and 2 are not sufficient

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Senior Manager
Joined: 06 Mar 2006
Posts: 490

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19 Jul 2007, 14:27
The answer to the question is C.

Let's pick numbers. Let's assume manager's avg salary is 10000

(1) This statement tells you that the avg salary of all employee is 15000 according to the number we picked. This statement alone is not sufficient.

(2) Statement 2 is not sufficient for the same reason.

But when you combine the two statement together you can solve for this.
manager's avg salary will be 10000
all employee avg salary will be 15000
director avg salary will be 30000

use knowledge of weighted average
M/(M+D)*(10000) + D/(M+D)*(30000)=15000
10M+30D=15M+15D
15D=5M
D/M=1/3
D/(M+D)=1/4 or 25% of total.

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Intern
Joined: 06 Apr 2007
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19 Jul 2007, 14:43
Let M be the # of managers, D be the # of Directors, and X be the average employee salary

statement 1. M(X-5000) = total salary for managers
NOT SUFF

statement 2. D(X+15000) = total salary for directors
NOT SUFF

statement 1+2

M(x-5000) + D(X+15000) = (M+D)X

MX-5000M + DX + 15000D = MX + DX

15000D = 5000M
3D = 1M

(C)

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19 Jul 2007, 14:43
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