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# Does the decimal equivalent of P/Q, where P and Q are

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Intern
Joined: 05 Oct 2007
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Does the decimal equivalent of P/Q, where P and Q are [#permalink]

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31 Oct 2007, 12:08
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Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only
a finite number of nonzero digits?
(1) P>Q
(2) Q=8

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Director
Joined: 11 Jun 2007
Posts: 910

Kudos [?]: 280 [0], given: 0

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31 Oct 2007, 12:14
rags wrote:
Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only
a finite number of nonzero digits?
(1) P>Q
(2) Q=8

i get B

in order to find if the number is a terminating decimal, we must know something about the denominator (numerator doesn't matter)

1) we know don't what P and Q are exactly but only their relationship to each other, not suff

2) Q = 8 then we know the decimal P/Q is finite (any combination of 2's and 5's would make it finite), sufficient

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SVP
Joined: 29 Aug 2007
Posts: 2472

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31 Oct 2007, 13:08
rags wrote:
Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only a finite number of nonzero digits?

(1) P>Q
(2) Q=8

Undoubtdely B: Since any integer divided by 8 turns into terminating deimal.

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Manager
Joined: 02 Aug 2007
Posts: 145

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31 Oct 2007, 14:07
GMAT TIGER wrote:
Undoubtdely B: Since any integer divided by 8 turns into terminating deimal.

6 & 3 would not be terminating. Are there any other integers with non terminating behaviors?

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Intern
Joined: 05 Oct 2007
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31 Oct 2007, 14:45
On more question with an incorrect OA, OA for this is E.

Anywho, the rule is :
a fraction in which the denominator has 2's or 5's ONLY as primes factors will always result in a terminating decimal

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Manager
Joined: 01 Oct 2007
Posts: 138

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01 Nov 2007, 03:47
rags wrote:
On more question with an incorrect OA, OA for this is E.

Anywho, the rule is :
a fraction in which the denominator has 2's or 5's ONLY as primes factors will always result in a terminating decimal

RAGS - then isn't 2 is the prime factor of 8? since either 2 or 5 is needed, then just 2 is sufficient to say that answer is B. am i right?

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Intern
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01 Nov 2007, 11:21
yes, as i said, OA is wrong for this one.

correct ans is B.

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CEO
Joined: 29 Mar 2007
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01 Nov 2007, 16:03
rags wrote:
Does the decimal equivalent of P/Q, where P and Q are positive integers, contain only
a finite number of nonzero digits?
(1) P>Q
(2) Q=8

In order to have a terminating decimal 1 of the 3 scenarios MUST be in place.

X, Y, and Z are any number. (I believe they can be any number, not sure if negatives would affect Z, I tested a few negative vales for Z make 2^Z --> 1/2^Z, seems ok though no forever decimals) Correct me on this if Im wrong please.

Anyway 3 scenarios are:

X/2^z X/5^z or X/2^z*5^y

There cannot be any other numbers in the bottom such as 3,7, etc... or it does not neccesarily consitute a terminating decimal!

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Re: DS-Division   [#permalink] 01 Nov 2007, 16:03
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