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# Does the product JKMN = 1?

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Does the product JKMN = 1? [#permalink]

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16 Dec 2005, 14:49
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5% (low)

Question Stats:

73% (01:44) correct 27% (00:43) wrong based on 199 sessions

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Does the product JKMN = 1?

(1) (JK)/(MN) = 1

(2) J= (1/K) and M = (1/N)
[Reveal] Spoiler: OA

Last edited by Bunuel on 01 Nov 2013, 01:07, edited 1 time in total.
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16 Dec 2005, 16:05
paki wrote:
Does the product JKMN = 1?

(1) (JK)/(MN) = 1

(2) J= (1/K) and M = (1/N)

B.

1) JK/MN = 1 ..... JK = MN , all we know is that JK and MN are equal, but could be any value, not just 1..... INSUFF

2) Substitute: (1/K)*K*(1/N)*N = 1.... SUFF
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16 Dec 2005, 21:48
(1) JK=1 MN=1 Yes

JK=1/3 MN=1/3 No.

Insufficient

(2) JK=MN=1

Sufficient to say JKMN=1

B.
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19 Dec 2005, 01:19
Posted: Fri Dec 16, 2005 1:49 pm Post subject: DS: JKMN

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19 Dec 2005, 01:31
paki wrote:
Does the product JKMN = 1?

(1) (JK)/(MN) = 1

(2) J= (1/K) and M = (1/N)

Let JK = 3 and MN =3 then jk/mn = 1 but jkmn # 1
Let jk = 1 and mn = 1 then jk/mn = 1 and jkmn = 1. So Stmt 1 is insuff.

From 2 we get jkmn = 1

So B,.
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Re: Does the product JKMN = 1? (1) (JK)/(MN) = 1 (2) J= (1/K) [#permalink]

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31 Oct 2013, 18:03
Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?
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Re: Does the product JKMN = 1? (1) (JK)/(MN) = 1 (2) J= (1/K) [#permalink]

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01 Nov 2013, 01:10
NvrEvrGvUp wrote:
Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?

jk = mn and jk = 1/mn does not exclude each other.

Does the product JKMN = 1?

(1) (JK)/(MN) = 1 --> JK=MN. The question becomes: does (MN)^2=1. We don't know that. Not sufficient.

(2) J= (1/K) and M = (1/N) --> JKMN = 1/K*K*1/N*N = 1. Sufficient.

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Re: Does the product JKMN = 1? (1) (JK)/(MN) = 1 (2) J= (1/K) [#permalink]

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01 Nov 2013, 12:40
Bunuel wrote:
NvrEvrGvUp wrote:
Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?

jk = mn and jk = 1/mn does not exclude each other.

Does the product JKMN = 1?

(1) (JK)/(MN) = 1 --> JK=MN. The question becomes: does (MN)^2=1. We don't know that. Not sufficient.

(2) J= (1/K) and M = (1/N) --> JKMN = 1/K*K*1/N*N = 1. Sufficient.

Thanks Bunuel, I understand now.

Is there a way to not fall into these types of traps? Working under time pressure, I saw that jk = 1/mn and assumed immediately that jk = mn would mean sufficient (since the answer would be "no" jkmn=/=1), forgetting that if mn = 1, it would actually be insufficient (since the answer would be "sometimes yes and sometimes no").

Is there a concept that I'm missing or is this more about working on fundamentals?
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Re: Does the product JKMN = 1? [#permalink]

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17 Sep 2016, 06:12
B is correct. Here's why:

(1) JK/MN = 1 --> We do not know the values the letters can take on, therefore INSUFFICIENT

(2) J = (1/K) & M = (1/N)

[(1/K)(K)]/[(1/N)(N)] = 1

SUFFICIENT
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Re: Does the product JKMN = 1? [#permalink]

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17 Sep 2016, 08:05
JK/MN = 1/1 yes
JK/MN = 2/2 no
A gone

S2
1/M*1/N*MN = 1 def

B
Re: Does the product JKMN = 1?   [#permalink] 17 Sep 2016, 08:05
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