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Does the product jkmn equal 1?

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paki
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Does the product jkmn equal 1? [#permalink] New post   Updated on: 07 Oct 2022, 08:18
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Does the product jkmn equal 1?

(1) \(\frac{jk}{mn} = 1\)

(2) \(j = \frac{1}{k}\) and \(m = \frac{1}{n}\)
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B

Originally posted by paki on 16 Dec 2005, 14:49.
Last edited by Bunuel on 07 Oct 2022, 08:18, edited 2 times in total.
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Re: Does the product jkmn equal 1? [#permalink] New post   16 Dec 2005, 16:05
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paki wrote:
Does the product JKMN = 1?

(1) (JK)/(MN) = 1

(2) J= (1/K) and M = (1/N)


B.

1) JK/MN = 1 ..... JK = MN , all we know is that JK and MN are equal, but could be any value, not just 1..... INSUFF

2) Substitute: (1/K)*K*(1/N)*N = 1.... SUFF
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Re: Does the product jkmn equal 1? [#permalink] New post   31 Oct 2013, 18:03
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Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?
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Re: Does the product jkmn equal 1? [#permalink] New post   01 Nov 2013, 01:10
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NvrEvrGvUp wrote:
Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?


jk = mn and jk = 1/mn does not exclude each other.

Does the product JKMN = 1?

(1) (JK)/(MN) = 1 --> JK=MN. The question becomes: does (MN)^2=1. We don't know that. Not sufficient.

(2) J= (1/K) and M = (1/N) --> JKMN = 1/K*K*1/N*N = 1. Sufficient.

Answer: B.
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Re: Does the product jkmn equal 1? [#permalink] New post   01 Nov 2021, 22:23
Bunuel wrote:
NvrEvrGvUp wrote:
Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?


jk = mn and jk = 1/mn does not exclude each other.

Does the product JKMN = 1?

(1) (JK)/(MN) = 1 --> JK=MN. The question becomes: does (MN)^2=1. We don't know that. Not sufficient.

(2) J= (1/K) and M = (1/N) --> JKMN = 1/K*K*1/N*N = 1. Sufficient.

Answer: B.


But what happens if K=0 or N=0? It would be wrong to assume 1/K*K=1 because of the indetermination. Can someone clarify?
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Re: Does the product jkmn equal 1? [#permalink] New post   02 Nov 2021, 01:26
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HermesM11 wrote:
Bunuel wrote:
NvrEvrGvUp wrote:
Bumping this up for a quick question.

Original question is asking whether jkmn = 1.

I rephrased to: does jk = 1/(mn) by dividing both sides by mn

Statement 1: jk/mn = 1 --> rephrase to jk = mn
Since jk = mn and does not equal 1/mn, I said this was sufficient.

Statement 2: j = 1/k; m = 1/n --> rephrase to jk = 1 and mn = 1
Sufficient

I chose answer choice D while the OA is B. Can someone please explain where I went wrong?


jk = mn and jk = 1/mn does not exclude each other.

Does the product JKMN = 1?

(1) (JK)/(MN) = 1 --> JK=MN. The question becomes: does (MN)^2=1. We don't know that. Not sufficient.

(2) J= (1/K) and M = (1/N) --> JKMN = 1/K*K*1/N*N = 1. Sufficient.

Answer: B.


But what happens if K=0 or N=0? It would be wrong to assume 1/K*K=1 because of the indetermination. Can someone clarify?


Division by 0 is not allowed: anything/0 is undefined. So, for (2) neither k nor n can be 0 because in this case 1/k and 1/n would be undefined and could not equal to real numbers j and m.

Does this make sense?
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Re: Does the product jkmn equal 1? [#permalink] New post   02 Nov 2021, 13:23
Bunuel wrote:
HermesM11 wrote:

But what happens if K=0 or N=0? It would be wrong to assume 1/K*K=1 because of the indetermination. Can someone clarify?


Division by 0 is not allowed: anything/0 is undefined. So, for (2) neither k nor n can be 0 because in this case 1/k and 1/n would be undefined and could not equal to real numbers j and m.

Does this make sense?


Got it! But it seems that I need to assume every number on GMAT is real, right? The question doesn’t mention it.

Posted from my mobile device
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Re: Does the product jkmn equal 1? [#permalink] New post   02 Nov 2021, 13:32
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HermesM11 wrote:
Bunuel wrote:
HermesM11 wrote:

But what happens if K=0 or N=0? It would be wrong to assume 1/K*K=1 because of the indetermination. Can someone clarify?


Division by 0 is not allowed: anything/0 is undefined. So, for (2) neither k nor n can be 0 because in this case 1/k and 1/n would be undefined and could not equal to real numbers j and m.

Does this make sense?


Got it! But it seems that I need to assume every number on GMAT is real, right? The question doesn’t mention it.

Posted from my mobile device


Yes, all numbers used are real numbers by default.
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Re: Does the product jkmn equal 1? [#permalink] New post   03 May 2023, 03:04
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Re: Does the product jkmn equal 1? [#permalink]
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