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Does x/n(s^2 + n^2 + t^2) = xn + yt + zs?

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Does x/n(s^2 + n^2 + t^2) = xn + yt + zs?  [#permalink]

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New post 10 Sep 2017, 04:47
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Difficulty:

  35% (medium)

Question Stats:

76% (01:35) correct 24% (01:14) wrong based on 21 sessions

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Re: Does x/n(s^2 + n^2 + t^2) = xn + yt + zs?  [#permalink]

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New post 10 Sep 2017, 04:56
Bunuel wrote:
Does \(\frac{x}{n}(s^2 + n^2 + t^2) = xn + yt + zs\)?

(1) xs = zn
(2) xt = yn



Clearly, individually the statements are not sufficient
and best way to start is by simplifying the equation

lets see combined
\(LHS=\frac{x}{n}(s^2 + n^2 + t^2)=\frac{xs^2}{n}+\frac{xn^2}{n}+\frac{xt^2}{n} =\frac{xs*s}{n}+xn+\frac{xt*t}{n}\)
substitute the values xs=zn and xt=yn
\(\frac{zn*s}{n}+xn+\frac{yn*t}{n}=zs+xn+yt=RHS\)

so ans is YES
suff

C
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Re: Does x/n(s^2 + n^2 + t^2) = xn + yt + zs?   [#permalink] 10 Sep 2017, 04:56
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