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doubt

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Joined: 15 Aug 2012
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doubt [#permalink]

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New post 15 Aug 2012, 19:15
28) The following 7 numbers are given: 2, 3, 5, 7, 11, 13, 17. Calling a product “quaternary” if it has any 4 of these numbers, how many different, odd, quaternary products can be created?

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New post 15 Aug 2012, 22:08
dualvessilva wrote:
28) The following 7 numbers are given: 2, 3, 5, 7, 11, 13, 17. Calling a product “quaternary” if it has any 4 of these numbers, how many different, odd, quaternary products can be created?


We need to select 4 of these numbers such that the product is odd. This means we cannot select 2. We can select any 4 numbers from the leftover 6 numbers and their product will be quaternary.

How do you select 4 out of given 6 distinct objects? 6C4 = 15

For more on this: http://www.veritasprep.com/blog/2011/11 ... binations/
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Re: doubt   [#permalink] 15 Aug 2012, 22:08
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