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# DS

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SVP
Joined: 16 Oct 2003
Posts: 1800

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23 Jun 2004, 20:53
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Kudos [?]: 170 [0], given: 0

Manager
Joined: 07 May 2004
Posts: 183

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Location: Ukraine, Russia(part-time)

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24 Jun 2004, 07:49
Bhai wrote:

1 is not suff., since its only implication is that -1 and 1 belong to S.

2 is suff., since -2 and 2 belong to S => -4 belongs to S.

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Senior Manager
Joined: 07 Oct 2003
Posts: 350

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Location: Manhattan

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24 Jun 2004, 09:41
clearly B (same reasoning as Emmanuel's)

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SVP
Joined: 16 Oct 2003
Posts: 1800

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24 Jun 2004, 17:32
Emmanuel wrote:
Bhai wrote:

1 is not suff., since its only implication is that -1 and 1 belong to S.

2 is suff., since -2 and 2 belong to S => -4 belongs to S.

Can you elaborate more on your point. I think I got it but not its not connecting..

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Director
Joined: 13 Nov 2003
Posts: 960

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Location: Florida

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24 Jun 2004, 20:29
B..

2 in S, this -2 is in S
a=2, b=-2 ---> a*b in S, or -4 in S.

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Manager
Joined: 08 Jun 2004
Posts: 245

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Location: INDIA

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25 Jun 2004, 11:58
my anz wud be

E ...
A) not suffiencient... since we know that 1 , -1 ARE THR...

B) not suffcient ... 2 and -2 are there....

combining we do not anything other than 1 -1 2 and -2...

also how can we assume that -a = b batli a=2 acc'' second statmt'' and if a is there we alsp have -a= -2 and if a is there we get b there... true but how and why do we have to assume that b=-a

and how can we multiply 2 and -2 its like -a* a and not ab...
some one help me ...

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25 Jun 2004, 11:58
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