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# ds: any quicker way?

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Senior Manager
Joined: 02 Feb 2004
Posts: 344

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20 Apr 2005, 15:32
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thanks;)
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Director
Joined: 07 Jun 2004
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20 Apr 2005, 17:31
is the answer to this 24 minutes

that is A will take 12 min to print 40 pages by itself so it will take 24 min to print 80 pages

i had to do this by quadratic equation and it was lengthy i cud nto fig out a shorcut if some one knwos please resond

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VP
Joined: 25 Nov 2004
Posts: 1482

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Re: ds: any quicker way? [#permalink]

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20 Apr 2005, 18:47
mirhaque wrote:
thanks;)

it is something killing.

a+b can do 50 pages in 6 minuets
a+b can do 80 pages in (6x80)/50 = 48/5 minuets ...................i

a can do 40 pages in (b+4) minuets
a can do 80 pages in 2(b+4) minuets
a can do 80/2(b+4) = 40/(b+4) pages in 1 minuet

b can do 40 pages in b minuets
b can do 80 pages in 2b minuets
b can do 80/2b= 40/b pages in 1 minuet

a+b can do [40/(b+4)]+[40/b] pages in 1 minuet
a+b can do 1 pages in 1/[40/(b+4)]+[40/b] minuetss
a+b can do 80 pages in {80/[40/(b+4)]+[40/b]} minuets ...............ii

the time taken by a+b in eq i must equal to the time taken by a+b in eq ii. therefore
48/5 minuets = 80/[{40/(b+4)}+(40/b)]minuets
5b^2-28b-96 = 0 ...................................iii

solving the above eq iii,

b = 8
a = b+4 = 12
a takes to complete 40 pages (b+4) = 12 minuets.
a takes to complete 80 pages 2(b+4) = 12x2=24 minuets.

its not an easy question. i did not like it. cus took too much

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Senior Manager
Joined: 19 Feb 2005
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21 Apr 2005, 00:53
my reasoning is not much shorter, anyway:
2 printers together: 25/3 pag/min
printer B= 40/x pag/min
printer A= 40/(X+4) pag/min

40/x+40/(x+4)=25/3
this is a 2nd degree equation, whose only positive solution is 8.
this means that printer A prints 40 pages in 8+4=12 minutes
and 80 pages in 24 minutes

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21 Apr 2005, 00:53
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# ds: any quicker way?

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