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# DS_divisibility m05 #36

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Director
Joined: 22 Aug 2007
Posts: 566

Kudos [?]: 72 [0], given: 0

If a, b, and c are positive distinct integers, is (a/b)/c an [#permalink]

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10 Oct 2007, 00:40
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

Kudos [?]: 72 [0], given: 0

Intern
Joined: 02 Aug 2007
Posts: 36

Kudos [?]: 43 [0], given: 0

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10 Oct 2007, 01:48
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b).
if c=2 and b=3, the result is not an integer.
if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

My ans. is E

Kudos [?]: 43 [0], given: 0

Intern
Joined: 02 Aug 2007
Posts: 36

Kudos [?]: 43 [0], given: 0

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10 Oct 2007, 01:52
ronneyc wrote:
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b).
if c=2 and b=3, the result is not an integer.
if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

My ans. is E

I missed (a) in stat 1 ... take b=4 and a=6

Kudos [?]: 43 [0], given: 0

VP
Joined: 09 Jul 2007
Posts: 1098

Kudos [?]: 144 [0], given: 0

Location: London

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10 Oct 2007, 04:05
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B
1. doesnt give info about others
2. suff.

(a/b)/c=a/bc

(b+c)/bc

1/b+1/c

since b and c are disticnt positive integers and b is not equal to c
the expression cannot be an integer

Kudos [?]: 144 [0], given: 0

VP
Joined: 09 Jul 2007
Posts: 1098

Kudos [?]: 144 [0], given: 0

Location: London

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10 Oct 2007, 04:32
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

tricky.
tempting to say C but it is B i think.

Kudos [?]: 144 [0], given: 0

Intern
Joined: 03 Mar 2006
Posts: 4

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10 Oct 2007, 05:59
Ravshonbek wrote:
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B
1. doesnt give info about others
2. suff.

(a/b)/c=a/bc

(b+c)/bc

1/b+1/c

since b and c are disticnt positive integers and b is not equal to c
the expression cannot be an integer

Welldone Rav. Got B 2!
_________________

winnie

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Senior Manager
Joined: 27 Aug 2007
Posts: 253

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10 Oct 2007, 08:40
Again late B

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Intern
Joined: 15 Mar 2007
Posts: 45

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10 Oct 2007, 10:39
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B.

Q: (a/b)/c = (a/bc)
S1: Insuff
S2: a = b+c ==> (b+c)/bc - is always a fraction for any set of distinct positive integers - Suff

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Intern
Joined: 08 Feb 2014
Posts: 10

Kudos [?]: 25 [2], given: 2

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26 Jun 2014, 23:18
2
KUDOS
A: Insuff. Given a, b are distinct integers, a/b must be an even integer. a=4, b=1 - true. a=9, b=3 - false. Both, true & false possible. Hence, inconclusive.
B: On simplifying, given b, c are distinct integers, (1/b + 1/c) must be an integer. For any b,c where b <> c, this is false. Hence, conclusive.

Thus, B.

Kudos [?]: 25 [2], given: 2

Re: DS_divisibility m05 #36   [#permalink] 26 Jun 2014, 23:18
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# DS_divisibility m05 #36

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