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# During a one day sale, a store sold each sweater of a

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Manager
Status: GMAT BATTLE - WIN OR DIE
Joined: 02 May 2011
Posts: 164

Kudos [?]: 108 [1], given: 13

Concentration: General Management, Entrepreneurship
GMAT Date: 12-22-2011
GPA: 3.81
WE: General Management (Hospitality and Tourism)
During a one day sale, a store sold each sweater of a [#permalink]

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18 Jun 2011, 07:56
1
KUDOS
6
This post was
BOOKMARKED
00:00

Difficulty:

25% (medium)

Question Stats:

69% (00:42) correct 31% (00:31) wrong based on 181 sessions

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During a one day sale, a store sold each sweater of a certain type for $30 more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale? (1) During the sale, the total revenue from the sale of these sweaters was$270.

(2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.

OPEN DISCUSSION OF THIS QUESTION IS HERE: during-a-one-day-sale-a-store-sold-each-sweater-of-a-92827.html
[Reveal] Spoiler: OA

Kudos [?]: 108 [1], given: 13

Current Student
Joined: 26 May 2005
Posts: 555

Kudos [?]: 239 [1], given: 13

Re: During a one day sale, a store sold each sweater of a [#permalink]

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18 Jun 2011, 08:38
1
KUDOS
3
This post was
BOOKMARKED
WishMasterUA wrote:
During a one day sale, a store sold each sweater of a certain type for 30$more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale? 1) During the sale, total revenue from of these sweaters was 270$.

2) During the sale, the store sold each of these sweaters at a price that was 50% greater tan the store's cost to purchase each sweater.

S = selling price
C = cost price
\Question tells us S= C+30

st 1 = Selling price * no of sweaters = 270.............. insufficient
st 2 = S = 1.5C
using information from question
1.5 C = C+30
0.5C = 30
C = 60
S =90
but no clue on revenue or number of sweaters sold. ............. insufficient

together 90* no of sweaters = 270
no of sweater = 3
sufficient

hence C

Kudos [?]: 239 [1], given: 13

Manager
Status: GMAT BATTLE - WIN OR DIE
Joined: 02 May 2011
Posts: 164

Kudos [?]: 108 [0], given: 13

Concentration: General Management, Entrepreneurship
GMAT Date: 12-22-2011
GPA: 3.81
WE: General Management (Hospitality and Tourism)
Re: During a one day sale, a store sold each sweater of a [#permalink]

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18 Jun 2011, 08:41
sudhir18n wrote:
WishMasterUA wrote:
During a one day sale, a store sold each sweater of a certain type for 30$more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale? 1) During the sale, total revenue from of these sweaters was 270$.

2) During the sale, the store sold each of these sweaters at a price that was 50% greater tan the store's cost to purchase each sweater.

S = selling price
C = cost price
\Question tells us S= C+30

st 1 = Selling price * no of sweaters = 270.............. insufficient
st 2 = S = 1.5C
using information from question
1.5 C = C+30
0.5C = 30
C = 60
S =90
but no clue on revenue or number of sweaters sold. ............. insufficient

together 90* no of sweaters = 270
no of sweater = 3
sufficient

hence C

thanks

Kudos [?]: 108 [0], given: 13

Manager
Status: folding sleeves up
Joined: 26 Apr 2013
Posts: 155

Kudos [?]: 137 [0], given: 39

Location: India
Concentration: Finance, Strategy
GMAT 1: 530 Q39 V23
GMAT 2: 560 Q42 V26
GPA: 3.5
WE: Consulting (Computer Hardware)
Re: During a one day sale, a store sold each sweater of a [#permalink]

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08 Sep 2014, 06:00
WishMasterUA wrote:
During a one day sale, a store sold each sweater of a certain type for 30$more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale? 1) During the sale, total revenue from of these sweaters was 270$.

2) During the sale, the store sold each of these sweaters at a price that was 50% greater tan the store's cost to purchase each sweater.

Soln:

SP= CP+30$P1: n (CP+30$)=270

don't know n and CP. So insufficient

P2:

SP= 3CP/2

dont know CP hence still insufficient

p1+p2=

3CP/2=CP+30$CP=60$
SP=90$Total sale= 270/90 = 3 sweaters !! Hence C Kudos [?]: 137 [0], given: 39 Math Expert Joined: 02 Sep 2009 Posts: 41884 Kudos [?]: 128929 [1], given: 12183 Re: During a one day sale, a store sold each sweater of a [#permalink] ### Show Tags 08 Sep 2014, 06:03 1 This post received KUDOS Expert's post 1 This post was BOOKMARKED WishMasterUA wrote: During a one day sale, a store sold each sweater of a certain type for$30 more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale?

(1) During the sale, the total revenue from the sale of these sweaters was \$270.

(2) During the sale, the store sold each of these sweaters at a price that was 50% greater than the store's cost to purchase each sweater.

Given: $$p=c+30$$

(1) (Revenue) = (price) * (# of sweaters sold) --> $$270=p*n=(c+30)n$$. Not sufficient to determine $$n$$.

(2) $$p=1.5c=c+30$$ --> $$c=60$$. Not sufficient.

(1)+(2) $$c=60$$ and $$270=(c+30)n=90n$$ --> $$n=3$$. Sufficient.

OPEN DISCUSSION OF THIS QUESTION IS HERE: during-a-one-day-sale-a-store-sold-each-sweater-of-a-92827.html
_________________

Kudos [?]: 128929 [1], given: 12183

Re: During a one day sale, a store sold each sweater of a   [#permalink] 08 Sep 2014, 06:03
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