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# During a spring season, a certain glacier surged at the rate of 1/4

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During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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02 Jul 2017, 01:57
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45% (medium)

Question Stats:

71% (02:25) correct 29% (01:53) wrong based on 85 sessions

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During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)

(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6

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During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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Updated on: 02 Jul 2017, 03:37
1
Bunuel wrote:
During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)

(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6

$$= \frac{1}{4} Mile * \frac{1}{25} days$$

$$= \frac{1}{4} Mile * \frac{5,280 Feet}{1 Mile}$$

$$= 1320 Feet$$

$$25 Days = 25 * 24 Hours = 600 Hours$$

$$= \frac{1320}{600}$$

$$= \frac{11}{5}$$ $$* \frac{Feet}{Hours}$$

We are looking for time taken for 1 feet

$$= \frac{5}{11}$$

Hence, Answer is C
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Originally posted by ydmuley on 02 Jul 2017, 02:28.
Last edited by ydmuley on 02 Jul 2017, 03:37, edited 1 time in total.
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Re: During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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02 Jul 2017, 02:29
Bunuel wrote:
During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)

(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6

$$1$$ mile $$= 5,280$$ feet

$$\frac{1}{4}$$ mile $$= \frac{5280}{4} = 1320$$ feet

$$1$$ day $$= 24$$ hours

$$25$$ days $$= 25 * 24 = 600$$ hours

Glacier surged at the rate of $$\frac{1}{4}$$ miles per $$25$$ days $$= \frac{1320}{600} = \frac{11}{5}$$

We need to find Time of hours taken by the glacier to cover $$1$$ foot. Let the time taken be $$= x$$

$$\frac{11}{5} = \frac{1}{x}$$

$$x = \frac{5}{11}$$

Answer (C)...
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During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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Updated on: 02 Jul 2017, 02:32
ydmuley wrote:
Bunuel wrote:
During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)

(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6

$$= \frac{1}{4} Mile * \frac{1}{25} days$$

$$= \frac{1}{4} Mile * \frac{5,280 Feet}{1 Mile}$$

$$= 1320 Feet$$

1320 Feet in 25 Day, so in 1 foot

$$= \frac{25}{1320}$$

$$= \frac{5}{264}$$

Hence, Answer is A

Hi ydmuley,
Its asking How many hours does it take the glacier to cover one foot, not days.

Originally posted by sashiim20 on 02 Jul 2017, 02:31.
Last edited by sashiim20 on 02 Jul 2017, 02:32, edited 1 time in total.
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Re: During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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02 Jul 2017, 02:32
Converting into relevant unit :
$$\frac{1}{4} miles = \frac{5280}{4} feet = 1320 feet$$

Since the glacier surged at the rate of 1320 feet in 25 days,
in 1 day it would have surged $$\frac{264}{5}$$ feet.

In an hour, it would have surged $$\frac{24*11}{5*24}$$ feet = $$\frac{11}{5}$$ feet
Since we have been asked to find out the number of hours,
the glacier travels 1 foot in - it must be $$\frac{5}{11}$$ hour(Option C)

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Re: During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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02 Jul 2017, 03:39
sashiim20 wrote:
ydmuley wrote:
Bunuel wrote:
During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)

(A) 5/264
(B) 6/25
(C) 5/11
(D) 11/5
(E) 25/6

$$= \frac{1}{4} Mile * \frac{1}{25} days$$

$$= \frac{1}{4} Mile * \frac{5,280 Feet}{1 Mile}$$

$$= 1320 Feet$$

1320 Feet in 25 Day, so in 1 foot

$$= \frac{25}{1320}$$

$$= \frac{5}{264}$$

Hence, Answer is A

Hi ydmuley,
Its asking How many hours does it take the glacier to cover one foot, not days.

Thank you so much for your suggestion sashiim20

Have edited the answer now.
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Re: During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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02 Jul 2017, 04:46
1/4 mile per 25 days so 1/(4*25)=0.01 mile per day
(0.01*5280)=22/10 feet per hour so we have 1 foot traveled in 5/11 hours.
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Re: During a spring season, a certain glacier surged at the rate of 1/4  [#permalink]

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02 Jul 2017, 21:46
Covert 5280 feet into 1/4 mile to check how many feet in 1/4 mile

5280/4= 1320 feet

Now as per given condition 1320 feet i.e, 1/4 mile is covered in 25 days and they have asked how many hours taken to complete 1 foot

So convert 25 days In hours which will be = 25*24 = 600

Now use unitary method to calculate no of hours to cover 1 foot = 600 (total no of hours to complete 1320 feet ) / 1320 (total no feet covered in 600 hours )

= 5/11

Which is option C

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Re: During a spring season, a certain glacier surged at the rate of 1/4   [#permalink] 02 Jul 2017, 21:46
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# During a spring season, a certain glacier surged at the rate of 1/4

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