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During a spring season, a certain glacier surged at the rate of 1/4
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02 Jul 2017, 01:57
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During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet) (A) 5/264 (B) 6/25 (C) 5/11 (D) 11/5 (E) 25/6
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During a spring season, a certain glacier surged at the rate of 1/4
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Updated on: 02 Jul 2017, 03:37
Bunuel wrote: During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)
(A) 5/264 (B) 6/25 (C) 5/11 (D) 11/5 (E) 25/6 \(= \frac{1}{4} Mile * \frac{1}{25} days\) \(= \frac{1}{4} Mile * \frac{5,280 Feet}{1 Mile}\) \(= 1320 Feet\) \(25 Days = 25 * 24 Hours = 600 Hours\) \(= \frac{1320}{600}\) \(= \frac{11}{5}\) \(* \frac{Feet}{Hours}\) We are looking for time taken for 1 feet \(= \frac{5}{11}\) Hence, Answer is C
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Originally posted by ydmuley on 02 Jul 2017, 02:28.
Last edited by ydmuley on 02 Jul 2017, 03:37, edited 1 time in total.



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Re: During a spring season, a certain glacier surged at the rate of 1/4
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02 Jul 2017, 02:29
Bunuel wrote: During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)
(A) 5/264 (B) 6/25 (C) 5/11 (D) 11/5 (E) 25/6 \(1\) mile \(= 5,280\) feet \(\frac{1}{4}\) mile \(= \frac{5280}{4} = 1320\) feet \(1\) day \(= 24\) hours \(25\) days \(= 25 * 24 = 600\) hours Glacier surged at the rate of \(\frac{1}{4}\) miles per \(25\) days \(= \frac{1320}{600} = \frac{11}{5}\) We need to find Time of hours taken by the glacier to cover \(1\) foot. Let the time taken be \(= x\) \(\frac{11}{5} = \frac{1}{x}\) \(x = \frac{5}{11}\) Answer (C)...



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During a spring season, a certain glacier surged at the rate of 1/4
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Updated on: 02 Jul 2017, 02:32
ydmuley wrote: Bunuel wrote: During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)
(A) 5/264 (B) 6/25 (C) 5/11 (D) 11/5 (E) 25/6 \(= \frac{1}{4} Mile * \frac{1}{25} days\) \(= \frac{1}{4} Mile * \frac{5,280 Feet}{1 Mile}\) \(= 1320 Feet\) 1320 Feet in 25 Day, so in 1 foot\(= \frac{25}{1320}\) \(= \frac{5}{264}\) Hence, Answer is AHi ydmuley, Its asking How many hours does it take the glacier to cover one foot, not days.
Originally posted by sashiim20 on 02 Jul 2017, 02:31.
Last edited by sashiim20 on 02 Jul 2017, 02:32, edited 1 time in total.



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Re: During a spring season, a certain glacier surged at the rate of 1/4
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02 Jul 2017, 02:32
Converting into relevant unit : \(\frac{1}{4} miles = \frac{5280}{4} feet = 1320 feet\)Since the glacier surged at the rate of 1320 feet in 25 days, in 1 day it would have surged \(\frac{264}{5}\) feet. In an hour, it would have surged \(\frac{24*11}{5*24}\) feet = \(\frac{11}{5}\) feet Since we have been asked to find out the number of hours, the glacier travels 1 foot in  it must be \(\frac{5}{11}\) hour(Option C)
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Re: During a spring season, a certain glacier surged at the rate of 1/4
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02 Jul 2017, 03:39
sashiim20 wrote: ydmuley wrote: Bunuel wrote: During a spring season, a certain glacier surged at the rate of 1/4 mile per 25 days. How many hours does it take the glacier to cover one foot? (1 mile = 5,280 feet)
(A) 5/264 (B) 6/25 (C) 5/11 (D) 11/5 (E) 25/6 \(= \frac{1}{4} Mile * \frac{1}{25} days\) \(= \frac{1}{4} Mile * \frac{5,280 Feet}{1 Mile}\) \(= 1320 Feet\) 1320 Feet in 25 Day, so in 1 foot\(= \frac{25}{1320}\) \(= \frac{5}{264}\) Hence, Answer is AHi ydmuley, Its asking How many hours does it take the glacier to cover one foot, not days. Thank you so much for your suggestion sashiim20Have edited the answer now.
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Re: During a spring season, a certain glacier surged at the rate of 1/4
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02 Jul 2017, 04:46
1/4 mile per 25 days so 1/(4*25)=0.01 mile per day (0.01*5280)=22/10 feet per hour so we have 1 foot traveled in 5/11 hours.
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Re: During a spring season, a certain glacier surged at the rate of 1/4
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02 Jul 2017, 21:46
Covert 5280 feet into 1/4 mile to check how many feet in 1/4 mile
5280/4= 1320 feet
Now as per given condition 1320 feet i.e, 1/4 mile is covered in 25 days and they have asked how many hours taken to complete 1 foot
So convert 25 days In hours which will be = 25*24 = 600
Now use unitary method to calculate no of hours to cover 1 foot = 600 (total no of hours to complete 1320 feet ) / 1320 (total no feet covered in 600 hours )
= 5/11
Which is option C
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Re: During a spring season, a certain glacier surged at the rate of 1/4
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