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# Each digit 1 through 5 is used exactly once to create a 5-di

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Manager
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Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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07 Jan 2013, 06:55
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Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible?

(A) 48
(B) 66
(C) 72
(D) 78
(E) 90
[Reveal] Spoiler: OA

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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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07 Jan 2013, 07:10
Total number of 5 digit numbers that can be formed = 5! = 120.
Total number of 5 digit numbers in which 3 and 4 are adjacent = 48. This can be calculated by taking 3 and 4 as a pair and considering positions where they can appear.
Number of 5 digit numbers in which 3 and 4 are not adjacent = Total number of 5 digit numbers - Total number of 5 digit numbers in which 3 and 4 are adjacent.
Ans = 120 - 48 = 72.
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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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07 Jan 2013, 10:32
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daviesj wrote:
Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible?

(A) 48
(B) 66
(C) 72
(D) 78
(E) 90

Such questions are best solved using the complement approach. You need to find arrangements in which 3 and 4 are not adjacent. Instead, work on finding the arrangements in which they are together since it is much easier to do.

Number of arrangements using 5 distinct digits = 5!
Number of arrangements in which 3 and 4 are adjacent - consider 3 and 4 together as one group. Now you have 4 numbers/groups to arrange which can be done in 4! ways. In each of these arrangements, 3 and 4 can be arranged as 34 or 43. So we need to multiply 4! by 2 to give all arrangements where 3 and 4 are adjacent to each other e.g. 34251, 43251, 23415, 32415 ...
Number of arrangements in which 3 and 4 are not adjacent = 5! - 2*4! = 72

Check out my detailed post on this concept: http://www.veritasprep.com/blog/2011/10 ... ts-part-i/
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Manager Joined: 04 Oct 2011 Posts: 221 Location: India Concentration: Entrepreneurship, International Business GMAT 1: 440 Q33 V13 GPA: 3 Followers: 0 Kudos [?]: 53 [0], given: 44 Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink] ### Show Tags 14 Jan 2013, 04:46 daviesj wrote: Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible? (A) 48 (B) 66 (C) 72 (D) 78 (E) 90 Total number of arrangements of 5 digit integer = 5! = 120 Let 3 and 4 be single digit like { 1 2 X 5 } This set arrangement is 4! = 24 As 3 and 4 can be interchanged between them 2(24) = 48 So 120-48 =72 Pls correct me if my solution is wrong! _________________ GMAT - Practice, Patience, Persistence Kudos if u like Manager Joined: 04 Jan 2013 Posts: 80 Followers: 0 Kudos [?]: 11 [0], given: 1 Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink] ### Show Tags 14 Jan 2013, 12:45 daviesj wrote: Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible? (A) 48 (B) 66 (C) 72 (D) 78 (E) 90 combinatorics and permutations eish..how do you guys make out on which way to use,whether combination or permutation,when you have such problem to solve?..when do you use permutation and when do you use combination? Posted from my mobile device Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7376 Location: Pune, India Followers: 2288 Kudos [?]: 15127 [0], given: 224 Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink] ### Show Tags 14 Jan 2013, 20:50 chiccufrazer1 wrote: daviesj wrote: Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible? (A) 48 (B) 66 (C) 72 (D) 78 (E) 90 combinatorics and permutations eish..how do you guys make out on which way to use,whether combination or permutation,when you have such problem to solve?..when do you use permutation and when do you use combination? Posted from my mobile device Discussed this dilemma here: http://www.veritasprep.com/blog/2011/11 ... binations/ _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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28 Nov 2014, 05:51
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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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01 Sep 2016, 00:35
Hello from the GMAT Club BumpBot!

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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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12 Nov 2016, 05:53
VeritasPrepKarishma wrote:
Now you have 4 numbers/groups to arrange which can be done in 4! ways.
VeritasPrepKarishma can you please explain how you draw the conclusion that there are 4 numbers/groups to arrange? There are only 2 numbers and the second part of your answer addresses switching their order. I am not understanding this conclusion. Thank you!
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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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14 Nov 2016, 05:36
raeann105 wrote:
VeritasPrepKarishma wrote:
Now you have 4 numbers/groups to arrange which can be done in 4! ways.
VeritasPrepKarishma can you please explain how you draw the conclusion that there are 4 numbers/groups to arrange? There are only 2 numbers and the second part of your answer addresses switching their order. I am not understanding this conclusion. Thank you!

You need to create a 5 digit integer using digits from 1 to 5. You will do that in various ways such as 12345, 23145, 45231 etc

If you club 3 and 4 together, you get a group {34}.

Now you have 3 leftover digits: 1, 2 and 5.
You have arrange 1, 2, 5 and {34}. So you have to arrange 4 digits/groups.
You can do this in various ways such as 12534, 21345 etc...

Since instead of {34}, you can have {43} too, you multiply by 2.
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Re: Each digit 1 through 5 is used exactly once to create a 5-di   [#permalink] 14 Nov 2016, 05:36
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