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Each employee on a certain task force is either a manager or

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Each employee on a certain task force is either a manager or [#permalink]

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20 Nov 2005, 01:23
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Each employee on a certain task force is either a manager or a director. What percent of employees in the task force are directors?

1) the average salary of the managers in the task force is \$5000 less than the average salary of all employees in task force.

2) the average salary of the directors in the task force is \$15000 more than the average salary of all employees in task force.

Last edited by tank on 20 Nov 2005, 12:00, edited 1 time in total.

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20 Nov 2005, 01:51
tank wrote:
Each employee on a certain task force is either a manager or a director. What percent of employees in the task force are directors?
1) the average salary of the managers in the task force is \$5000 less than all employees in task force.
2) the average salary of the directors in the task force is \$15000 more than all employees in task force.

can you clarify on bold part pls..does it mean that avg salary of directors is more than "AVERAGE" of all employee's salary or their NUMBER?
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20 Nov 2005, 09:23
tank wrote:
Each employee on a certain task force is either a manager or a director. What percent of employees in the task force are directors?
1) the average salary of the managers in the task force is \$5000 less than the average salary of all employees in task force.
2) the average salary of the directors in the task force is \$15000 more than the average salary of all employees in task force.

I changed to it reflect the actual question. Sorry, i was being lazy...

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25 Nov 2005, 08:31
Seems too obviously easy to be E. E is the default trap answer that ETS wants us to choose. Working backwards, and using a little reverse psychological intuition, I think the answer is C.

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25 Nov 2005, 09:39
C)...we are looking for d/(d+m) ?

average salary of all employers is a. m for manager. d for directors.

2) a+15000. same as above.insuff

1)+2) (m(a-5000)+d(a+15000))/m+d=a...ma-5000m+da+15000d=ma+da...
15000d=5000m...3d=m...suff
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27 Nov 2005, 06:15
Ah, I see it. I misread the Q and thought (1) was 5000 less than average director's salary.

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30 May 2008, 11:10
i think the answer is C.

i think it is a gmat prep question
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30 May 2008, 18:49
tank wrote:
Each employee on a certain task force is either a manager or a director. What percent of employees in the task force are directors?

1) the average salary of the managers in the task force is \$5000 less than the average salary of all employees in task force.

2) the average salary of the directors in the task force is \$15000 more than the average salary of all employees in task force.

1. average salary of all employess is A
2. percentage of directores is D
3. from 1: (A-5000)*(100-D)
4. from 2: (A+15000)*D
5. combining 1 and 2 statement: 100A=(A-5000)*(100-D) + (A+15000)*D
6. D=25
7. OA is C
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