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# Each employee on a certain task force is either a manager or

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Manager
Joined: 03 Jul 2005
Posts: 191

Kudos [?]: 12 [0], given: 0

Location: City
Each employee on a certain task force is either a manager or [#permalink]

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12 Nov 2006, 23:37
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Each employee on a certain task force is either a manager or a director. What percent of the employees on the task force are directors?

A) The average (arithmetic mean) salary of the managers on the task force is \$5,000 less than the average salary of all employees on the task force

B) The average (arithmetic mean) salary of the directors on the task force is \$15,000 greater than the average salary of all employees on the task force.

Could you work how to finish the question to prove what the answer is.

Kudos [?]: 12 [0], given: 0

VP
Joined: 25 Jun 2006
Posts: 1161

Kudos [?]: 203 [0], given: 0

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13 Nov 2006, 01:45
guessing E.

i can't working out the answer.

Kudos [?]: 203 [0], given: 0

Director
Joined: 06 Feb 2006
Posts: 893

Kudos [?]: 129 [0], given: 0

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13 Nov 2006, 01:57
Hm...

Taking both statements together....

Sum of wages =S (all empoyees) Sd(directors) Sm(managers)
# of managers = m
# of directors = d (need to find this)
# of all employees = a (need to find this)
the average salary = y

Average salary of all employees: S/a=y

from 1) Sm/m=y-5
from 2) Sd/d=y+15

Did no detailed calculations, however feel that the answer is E....

Kudos [?]: 129 [0], given: 0

VP
Joined: 25 Jun 2006
Posts: 1161

Kudos [?]: 203 [0], given: 0

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13 Nov 2006, 02:01
all we need is to find the ratio m/d, but it seems not possible.

Kudos [?]: 203 [0], given: 0

Manager
Joined: 03 Jul 2005
Posts: 191

Kudos [?]: 12 [0], given: 0

Location: City

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13 Nov 2006, 04:50
Apparently the OA is C, but I cannot see how!!

Kudos [?]: 12 [0], given: 0

13 Nov 2006, 04:50
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