Each first-year student at a certain school selects either

Each fi…rst-year student at a certain school selects either the traditional curriculum or the modern curriculum. Of the fi…rst-year students at the school, 65 percent selected the modern curriculum and the rest selected the traditional curriculum. What percent of the fi…rst-year students are female?

(1) Twice as many female fir…st-year students selected the modern curriculum than selected the traditional curriculum:Not sufficient.

(2) Of the fi…rst-year students who selected the traditional curriculum, 55 percent are female:Not sufficient.

(1)+(2) As you can see x from (1) equals to 19.25 from (2), so 3x (percent of the female students) equals to 3*19.2557.75%. Sufficient.

Answer: C.

Hope it's clear.
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Bunuel, I approcahed the problem in the same way and got C as the answer , Although Have question.
How can the number of Female students be 19.25? It has to be a whole number isnt it? People can't be fractions.

The question is asking for percent. so it can be a fraction.

Just a small point for discussion,
when they say Traditional or Modern it means T +M- Both.

So T+M-Both =100
now when they say T= 65 and the rest is Modern, how are we assuming that M= 35 and Both = 0 ?

It could be T= 65, M= 45 and Both = 10 ( or any other combination that leads to a 100% )
or T= 65, M= 35, Both = 0 ( as done in the problem)

if there are no students taking both , then Both = 0 then of course the problem is easy to understand, but why and how are we assuming that B= 0, when it says T or M, which means T+M-both .

Nowhere does it state that the student cannot take both,is this common knowledge?

Thanks.
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Yes, from "each fi…rst-year student at a certain school selects either the traditional curriculum or the modern curriculum" we can safely assume that neither of the students selects both.
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Hi Experts,

I got A. Could you please check the below math and correct if I am wrong.

Let x = total no. of students and y = no of female students. To find, (y/x)*100

Given MC = 0.65x, and from (1) 2y = 0.65x i.e. y=0.65x/2
So we have x and y in terms of x, therefore percent of female students is (0.65/2)*100.

B is not sufficient, so the answer for me comes out to be A.

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