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Each machine at a toy factory assembles a certain kind of toy at a co

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Re: Each machine at a toy factory assembles a certain kind of toy at a co  [#permalink]

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New post 12 Apr 2020, 04:23
Ratio Approach:
Assume total 100 machines.
Ratio of Time taken- Old:New = 3:2
So, Ratio of Speed- Old : New =2:3 ( It means new machine can produce 1.5 times more toys per unit of time than Old one)
So, if 60 old machines produce 60 toys, 40 new machines will produce 40 x 1.5 = 60 toys. Total= 60+60 =120 (20% more)
Ans: A
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Re: Each machine at a toy factory assembles a certain kind of toy at a co  [#permalink]

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New post 12 May 2020, 10:08
msu6800 wrote:
One old toy in every 3 min, so 20 old toys in 60 mins.
One new toy in every 2 mins, so 30 toys in 60 mins.
So percentage increase= [(30-20)/20]*(40℅)=1/5=20%

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VeritasKarishma Bunuel egmat,

I find this approach pretty easy and to the point , plz advice whether this is okay ?
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Re: Each machine at a toy factory assembles a certain kind of toy at a co  [#permalink]

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New post 14 May 2020, 22:21
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LeenaSai wrote:
msu6800 wrote:
One old toy in every 3 min, so 20 old toys in 60 mins.
One new toy in every 2 mins, so 30 toys in 60 mins.
So percentage increase= [(30-20)/20]*(40℅)=1/5=20%

Posted from my mobile device



VeritasKarishma Bunuel egmat,

I find this approach pretty easy and to the point , plz advice whether this is okay ?


Yes, perfectly fine.
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Re: Each machine at a toy factory assembles a certain kind of toy at a co  [#permalink]

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New post 15 May 2020, 23:20
Using longer sentences.

What we know
>1 machine produces 1 toy every 3 mins
> hence 1 machine makes 1/3 or a toy in 1 min
> hence 1 machine will make X Toys @ 1/3 *60
> hence 1 machine will make 20 toys in 60 mins or 1hr

> 40% of the machines are to be replaced
>>hence 60% of the machine will work at the same rate

Let's solve
1. Let's say 10 machines are there
> 10 machines * 20 toys per machine = 200 toys in 60 mins of 1/3. THE ORIGINAL PRODUCTION QUANTITY

2. Since 40% are replaced
PART 1. NEW MACHINE output
>((40/100)*10*) = number of new machines
> 4 new machines
> 4 NM make 1 toy every 2 mins individually
> hence 1 NM work @ 1/2 toy every min
> hence 1 NM 1/2 toy * 60 mins
> hence 1 NM 30 toys in 1 hour
> hence 4 NM make 30 *4 in 1 hour
> Total NM output = 120 in 1 hour

PART 2. Original Machine output
> 6 machines * 20 toys per 1 hour
> hence OM make 6*20 per 1 hour
> hence OM makes 120 per 1 hour

PART 3.
NM + OM = 240

PART 4.
> Change/Original * 100%
> ((240-200)/200)* 100%
> hence (40/200)*100
> hence 20%
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Re: Each machine at a toy factory assembles a certain kind of toy at a co  [#permalink]

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New post 19 Jun 2020, 05:37
Hi, can you pls tell me the approach to this question to solve it more efficiently?

JeffYin wrote:
Here are my two GMAT Timing Tips for this question, both of which have been demonstrated in this thread already:

1) Work with integers instead of fractions or decimals: By converting the rate from 1/3 or 1/2 toy per minute to 20 or 30 toys per hour, you can make the calculations easier and faster.

2) Choose 100 as the original value for a percent change: You can set the original value for toys per hour to 100 by assuming that you have 5 machines, and converting 40% of these 5 machines is also an easy calculation (2 machines). When you calculate that the new value for toys per hour is 120, it’s easy to see that this is a 20% increase over the original value of 100.

The links above will have growing lists of questions that you can use to practice each timing tip.

Please let me know if you have any questions about how I would do this question most efficiently, and I'd be happy to post a video solution!
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Re: Each machine at a toy factory assembles a certain kind of toy at a co  [#permalink]

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New post 19 Jun 2020, 18:37
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Hi avyagarg,

Most GMAT questions can be solved in more than one - and there's often a strategic approach that is faster than a traditional 'math' approach. This question can be solved by TESTing VALUES.

We're told that each machine can currently create one toy every 3 minutes. We're then told that 40 percent of the machines will be replaced by new machines that can assemble one toy every 2 minutes. We're asked for the percent increase in the number of toys assembled in one hour by all the machines at the factory.

Since we're replacing 40% of the machines, let's TEST 5 total machines.
One toy every 3 minutes = 20 toys/hour
One toy every 2 minutes = 30 toys/hour

Original Machines
(5 machines)(20 toys/hour) = 100 toys/hour produced

New 'mix' of Machines
(3 machines)(20 toys/hour) = 60 toys/hour produced
(2 machines)(30 toys/hour) = 60 toys/hour produced
Total = 120 toys/hour produced

Percent Change = (New - Old)/(Old) = (120 - 100)/100 = 20/100 = 20%



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Re: Each machine at a toy factory assembles a certain kind of toy at a co   [#permalink] 19 Jun 2020, 18:37

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