Author 
Message 
TAGS:

Hide Tags

Current Student
Joined: 29 Jan 2005
Posts: 5218

Each member of a pack of 55 wolves has either brown or blue [#permalink]
Show Tags
25 Mar 2006, 22:17
1
This post received KUDOS
2
This post was BOOKMARKED
Question Stats:
51% (02:53) correct
49% (02:00) wrong based on 199 sessions
HideShow timer Statistics
Each member of a pack of 55 wolves has either brown or blue eyes and either a white or a grey coat. If there are more than 3 blueeyed wolves with white coats, are there more blueeyed wolves than browneyed wolves? (1) Among the blueeyed wolves, the ratio of grey coats to white coats is 4 to 3. (2) Among the browneyed wolves, the ratio of white coats to grey coats is 2 to 1. OPEN DISCUSSION OF THIS QUESTION IS HERE: eachmemberofapackof55wolveshaseitherbrownorblue122299.html
Official Answer and Stats are available only to registered users. Register/ Login.



VP
Joined: 21 Sep 2003
Posts: 1057
Location: USA

My pick would be E.
1. Doesn't provide any info about Brown eyed wolves
2. Doesn't provide any info about Blu eyed wolves
Combining:
Since only the ratios are provided. There could be several pssobilities that satisfy 1 & 2.
BR:BLU = (6,49), (27,28), (48,7)
Hence E.
_________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
 Bernard Edmonds



SVP
Joined: 14 Dec 2004
Posts: 1689

Yeah, how I approached it is using table method.
if "x" is the total number of blue eyed wolves,
then (3x/7) > 3  (from the ratio given)
=> x > 7
Since, x > 7, the answer can be YES or NO.
Using Statement2, or even together, will not solve this problem!



Current Student
Joined: 29 Jan 2005
Posts: 5218

1
This post received KUDOS
Well, Vivek, the answer given is not (E). I guess that leaves you with only one other choice....
Try again, buddy.



VP
Joined: 21 Sep 2003
Posts: 1057
Location: USA

giddi77 wrote: My pick would be E.
1. Doesn't provide any info about Brown eyed wolves 2. Doesn't provide any info about Blu eyed wolves
Combining: Since only the ratios are provided. There could be several pssobilities that satisfy 1 & 2.
BR:BLU = (6,49), (27,28), (48,7)
Hence E.
Looks like MATT picked tis bad boy to trouble us. I am guessing this from MGMAT or Kaplan.
I would change it to C. since
BR:BLU = (6,49), (27,28), (48,7)
but (48,7) is not a possible solution as it would make the number of Blue Eyed White coats = 3 and hence is ruled out .
Now the only possibilities are
BR: BLU = (6,49) & (27,28)
In both cases BR < BLU, which answers the question.
Is C the answer?
_________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
 Bernard Edmonds



SVP
Joined: 14 Dec 2004
Posts: 1689

Hehehehe,
I changed it to "C" too
Basically chose the pair of numbers that satisfy the requirement!
phew....MATT, this is brutal



Current Student
Joined: 29 Jan 2005
Posts: 5218

Yep, OA is (C)
OE: http://www.manhattangmat.com/ChallengeP ... cfm?ID=235
BTW Giddi: How did you determine it was a MGMAT problem? By difficulty? Or pattern recognition??



VP
Joined: 21 Sep 2003
Posts: 1057
Location: USA

GMATT73 wrote: Yep, OA is (C) OE: http://www.manhattangmat.com/ChallengeP ... cfm?ID=235BTW Giddi: How did you determine it was a MGMAT problem? By difficulty? Or pattern recognition??
Just a guess based on the difficulty...
When you have more than 1 possible solution and still the answer is not E => It must be a MGMAT question!
_________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
 Bernard Edmonds



Manager
Joined: 28 Dec 2005
Posts: 117

giddi
could you explain how you got the numbers (6,49) and (28,27)
thanks



GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

3
This post received KUDOS
myc2004 wrote: giddi
could you explain how you got the numbers (6,49) and (28,27)
thanks
(1) Total of Blue eyed wolves = 7 parts. So the total number must be a multiple of 7. This could be 7,14,21,28...etc and then the remainder will be browneyed wolves. Insufficient as we can't compute the number of brown eyed wolves.
(2) Same problem as (1)
Using both,
Blueeyed wolves have 7 parts
Browneye wolves has 3 parts.
So Blueeyed wolves is a multiple of 7, such that remainder of wolves is a multiple of 3. Could be blue:brown = (7,48) (28,27) (49,6)
But then we're told number of blueeyed white coat wolves is more than 3. So (7,48) is out. We're now left with blue:brown = (28,27) and (49,6).
Ans C



GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16029

Re: Each member of a pack of 55 wolves has either brown or blue [#permalink]
Show Tags
31 Jan 2014, 06:36
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources



Math Expert
Joined: 02 Sep 2009
Posts: 39754

Re: Each member of a pack of 55 wolves has either brown or blue [#permalink]
Show Tags
31 Jan 2014, 08:11
2
This post received KUDOS
Expert's post
4
This post was BOOKMARKED
Each member of a pack of 55 wolves has either brown or blue eyes and either a white or a grey coat. If there are more than 3 blueeyed wolves with white coats, are there more blueeyed wolves than browneyed wolves?Look at the matrix below: "There are more than 3 blueeyed wolves with white coats" means that # of wolves which have blue eyes AND white coats is more than 3. The question asks whether there are more blueeyed wolves (blue box) than browneyed wolves (brown box). (1) Among the blueeyed wolves, the ratio of grey coats to white coats is 4 to 3. Not sufficient on its own. (2) Among the browneyed wolves, the ratio of white coats to grey coats is 2 to 1. Not sufficient on its own. (1)+(2) When taken together we get the flowing matrix: Wolves (1)+(2).png[/attachment]Notice that x and y must be integers (they represent some positive multiples for the ratios given in the statements). So, we have that 3y+7x=55. After some trial and error we can find that this equation has only 3 positive integers solutions: y=2 and x=7 > 3y+7x=6+49=55; y=9 and x=4 > 3y+7x=27+28=55; y=16 and x=1 > 3y+7x=48+7=55; Now, the third solution (x=1) is not valid, since in this case # of wolves which have blue eyes AND white coats becomes 3x=3, so not more than 3 as given in the stem. As for the first two cases, in both of them 7x is more than 3y (49>6 and 28>27), so we can answer definite YES, to the question whether there are more blueeyed wolves (blue box) than browneyed wolves (brown box). Answer: C. OPEN DISCUSSION OF THIS QUESTION IS HERE: eachmemberofapackof55wolveshaseitherbrownorblue122299.html
_________________
New to the Math Forum? Please read this: All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics




Re: Each member of a pack of 55 wolves has either brown or blue
[#permalink]
31 Jan 2014, 08:11








Similar topics 
Author 
Replies 
Last post 
Similar Topics:


3


Each of the balls in a jar is either red, green or blue. If

anon1 
3 
02 Dec 2012, 08:59 

41


Each member of a pack of 55 wolves has either brown or blue

LalaB 
15 
23 Mar 2017, 16:47 

11


Each of the 25 balls in a certain box is either red, blue,

changhiskhan 
4 
24 Jul 2014, 23:57 

4


Each of the 25 balls in a certain box is either red, blue

above720 
15 
30 Dec 2014, 07:37 

188


Each of the 25 balls in a certain box is either red, blue or

lexis 
42 
25 Jun 2017, 18:34 



