It is currently 25 Sep 2017, 08:22

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# each of the 6 teams in the league played each of the other

Author Message
Eternal Intern
Joined: 07 Jun 2003
Posts: 465

Kudos [?]: 163 [0], given: 0

Location: Lone Star State
each of the 6 teams in the league played each of the other [#permalink]

### Show Tags

08 Jun 2003, 18:19
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did the 6 teams play?

Kudos [?]: 163 [0], given: 0

Manager
Joined: 03 Jun 2003
Posts: 83

Kudos [?]: 1 [0], given: 0

Location: Uruguay

### Show Tags

09 Jun 2003, 11:27
I have the same answer. Just another approach

First team has to play 10 games (6 teams, so 5 games. As they play twice, there are 10 games)
Second team play the same 10 games, but the ones with team one are already counted, so 8 games
Third the same as second team 6 games
Fourth 4 games
Fifth 2 games
Sixth 0

total 10+8+6+4= 30

Kudos [?]: 1 [0], given: 0

Manager
Joined: 03 Jun 2003
Posts: 83

Kudos [?]: 1 [0], given: 0

Location: Uruguay

### Show Tags

09 Jun 2003, 11:28
Sorry, 10+8+6+4+2 = 30

I forgot the 2

Kudos [?]: 1 [0], given: 0

SVP
Joined: 14 Dec 2004
Posts: 1685

Kudos [?]: 167 [0], given: 0

### Show Tags

14 Mar 2006, 20:50
6C2*2 = 30.

Total number of pairs possible = 6C2.
Number matches between any two paris = 2
So, total matches = 6C2 * 2.

Nice one from the golden grave!

Kudos [?]: 167 [0], given: 0

Manager
Joined: 20 Feb 2006
Posts: 214

Kudos [?]: 14 [0], given: 0

### Show Tags

14 Mar 2006, 20:51
I too got 30 and the logic is same as that of MBA04's.
tzolkin's approach is simpler. I learnt one more application of combinations today. Thanks tzolkin.

Kudos [?]: 14 [0], given: 0

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5039

Kudos [?]: 425 [0], given: 0

Location: Singapore

### Show Tags

14 Mar 2006, 22:26
# of ways = 6C2 * 2 = 30 ways

Use combination because we are interested in grouping and not ordering

Kudos [?]: 425 [0], given: 0

14 Mar 2006, 22:26
Display posts from previous: Sort by