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Each of the marbles in a bag is either blue, red, or green, and there

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Bunuel
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Each of the marbles in a bag is either blue, red, or green, and there [#permalink] Each of the marbles in a bag is either blue, red, or green, and there   27 Nov 2018, 00:01
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A
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E

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78% (01:39) correct 22% (01:55) wrong based on 82 sessions
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Each of the marbles in a bag is either blue, red, or green, and there is at least one marble of each color in the bag. If the bag contains twice as many blue marbles as red marbles, then the number of red marbles in the bag divided by the total number of marbles in the bag is

A. less than 1/3
B. equal to 1/3
C. between 1/3 and 1/2
D. between 1/2 and 2
E. greater than 2
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A
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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink] Each of the marbles in a bag is either blue, red, or green, and there   27 Nov 2018, 08:43
Bunuel
Each of the marbles in a bag is either blue, red, or green, and there is at least one marble of each color in the bag. If the bag contains twice as many blue marbles as red marbles, then the number of red marbles in the bag divided by the total number of marbles in the bag is

A. less than 1/3
B. equal to 1/3
C. between 1/3 and 1/2
D. between 1/2 and 2
E. greater than 2


Let R=1 , G=1 since B= 2*R= 2
Total 4
Red/total= 1/4 = .25
IMO option A is correct..
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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink] Each of the marbles in a bag is either blue, red, or green, and there   15 Sep 2019, 00:55
Is this just about plugging in or is there another logical way to see this immediately?
My first thought was that this is un-solvable without knowing anything about G, but it seems to work with every combination.
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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink] Each of the marbles in a bag is either blue, red, or green, and there   30 Sep 2019, 18:46
Bunuel
Each of the marbles in a bag is either blue, red, or green, and there is at least one marble of each color in the bag. If the bag contains twice as many blue marbles as red marbles, then the number of red marbles in the bag divided by the total number of marbles in the bag is

A. less than 1/3
B. equal to 1/3
C. between 1/3 and 1/2
D. between 1/2 and 2
E. greater than 2

Since we need to consider a common approach, the best will be to assume the least number of marbles.
R=1,B=2,G=1

R=1/4, which is less than 1/3.

Hence A
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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink] Each of the marbles in a bag is either blue, red, or green, and there   05 Oct 2019, 16:49
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Bunuel
Each of the marbles in a bag is either blue, red, or green, and there is at least one marble of each color in the bag. If the bag contains twice as many blue marbles as red marbles, then the number of red marbles in the bag divided by the total number of marbles in the bag is

A. less than 1/3
B. equal to 1/3
C. between 1/3 and 1/2
D. between 1/2 and 2
E. greater than 2

Let’s let r = the number of red marbles, b = the number of blue marbles, and g = the number of green marbles. We also know that b = 2r. So the ratio of red marbles to the total number of marbles is r/(r + 2r + g) = r/(3r + g), which is less than r/(3r) or 1/3.

Answer: A
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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink]
05 Oct 2019, 16:49
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Bunuel
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