It is currently 23 Jun 2017, 19:26

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# each side of square ABCD has length 1, the length of line

Author Message
Manager
Joined: 06 Nov 2008
Posts: 53
each side of square ABCD has length 1, the length of line [#permalink]

### Show Tags

20 Nov 2008, 09:12
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

each side of square ABCD has length 1, the length of line
Segment CE is 1, and the length of line segment BE is equal to the length
Of line segment DE. What is the area of the triangular region BCE?
a. 1/3 b. (2^-2 )/4 c. 1/2
d. (2^-2)/2 e. 3/4
Intern
Joined: 20 Aug 2008
Posts: 1

### Show Tags

22 Nov 2008, 06:49
Hi
The answer to this question is b. (2^-2 )/4.
Intern
Joined: 04 Jun 2008
Posts: 17

### Show Tags

23 Nov 2008, 23:36
1
KUDOS
line segment BC = line segment DC
BE=DE(given)
and CE is common between triangles CDE and BCE.so they are similar.
= <DCE = <BCE = 45 or point E lies on the diagonal.

so area of triangle BCE = BC * CE *sin(45)/2

=> 1/(2*sqrt(2)) = sqrt(2)/4

Manager
Joined: 18 Nov 2008
Posts: 116

### Show Tags

24 Nov 2008, 02:08
emailsector, gmat isn't testing knowledge of trigonometric formulas, so there is always other ways to get a right answer. I'm also getting 1/2sqrt2 = sqrt2/4, but it isn't among answer choices for b = 2^-2/4 = 1/16, which is impossible. So, I think there is a mistake in the answer choices.

My solwing way: from E draw a perpendicular line to BC and call it EF. Angle EFC = 90, FCE = 45 = FEC. So, with given EC = 1 we get EF = 1/sqrt2 (45:45:90 => 1:1:sqrt2). Area of EFC = 1/2 x 1 x 1/sqrt2 = 1/2sqrt2 = sqrt2/4.
Re: square ABCD--25   [#permalink] 24 Nov 2008, 02:08
Display posts from previous: Sort by