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Ed throws a blue die and a red die. How many combinations are there in

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Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 03 Oct 2016, 23:23
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A
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C
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Question Stats:

79% (01:05) correct 21% (01:43) wrong based on 186 sessions

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Ed throws a blue die and a red die. How many combinations are there in which the two dice do not yield the same result and the sum of the results is not 9?

A. 10
B. 24
C. 26
D. 30
E. 36

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Re: Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 04 Oct 2016, 02:20
1
2
Bunuel wrote:
Ed throws a blue die and a red die. How many combinations are there in which the two dice do not yield the same result and the sum of the results is not 9?

A. 10
B. 24
C. 26
D. 30
E. 36


Tricky one...

Total number of combination is 6*6 = 36..

Condition 1: we shouldn't get the same number... (1,1)(2,2)(3,3)(4,4)(5,5)(6,6) - 6 combinations.

condition 2: We shouldn't get the 9 as the sum (4,5)(5,4)(3,6)(6,3) - 4 combinations...

Total = 36 - 10 = 26.

IMO option c.
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Re: Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 04 Oct 2016, 03:50
Bunuel wrote:
Ed throws a blue die and a red die. How many combinations are there in which the two dice do not yield the same result and the sum of the results is not 9?

A. 10
B. 24
C. 26
D. 30
E. 36


IMO C
Two dice yielding same result has 6 variations (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)
Two dice yielding a sum of 9 has 4 variations (3,6), (4,5), (6,3), (5,4)
When 2 dice are rolled you have total 36 outcomes
So required is 36-10= 26 outcomes
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Re: Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 09 Oct 2016, 13:32
With VINAYAK Shenoy & msk0657

IMHO with (C) for this one..

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Re: Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 17 Nov 2016, 18:42
Total = 36 (b/c 6x6)

Total Values that will give 9 =
3,6
6,3
4,5
5,4

This leaves 32 combinations that will not sum to 9

Lastly, we know that the two dice cannot produce the same number, thus we can subtract out the following:
1,1
2,2
3,3
4,4
5,5
6,6

This leaves us with 32-6 = 26

C.
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Re: Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 29 Nov 2016, 16:43
1
Bunuel wrote:
Ed throws a blue die and a red die. How many combinations are there in which the two dice do not yield the same result and the sum of the results is not 9?

A. 10
B. 24
C. 26
D. 30
E. 36


We can create the following equation:

(Total number of ways to roll two dice) = (number of ways two dice do not yield the same result and do not sum to 9) + (number of ways two dice do yield the same result) + (number of ways two dice do sum to 9)

Let’s rearrange this equation, yielding:

(The number of ways two dice do not yield the same result and do not sum to 9) = (Total number of ways to roll two dice) - (number of ways two dice do yield the same result) - (number of ways two dice do sum to 9)

Since there are 6 numbers on each die, the total number of outcomes from rolling two dice is 6 x 6 = 36.

There are 6 ways that two dice can yield the same result:

1 - 1
2 - 2
3 - 3
4 - 4
5 - 5
6 - 6

There are 4 ways the two dice can yield a sum of 9:

6 - 3
3 - 6
4 - 5
5 - 4

So there are 36 - 6 - 4 = 26 ways to NOT yield the same result and NOT yield a sum of 9 from rolling two dice.

Answer: C
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Re: Ed throws a blue die and a red die. How many combinations are there in [#permalink]

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New post 07 Apr 2017, 15:29
alternatively, list all combinations...they are not that many of them...<36...but will take longer...i solved in under 2 mins through this method...
1-2
1-3
1-4
1-5
1-6
2-1
2-3
2-4
2-5
2-6
3-1
3-2
3-4
3-5
3-6 - out (sum is 9)
4-1
4-2
4-3
4-5 - out (sum is 9)
4-6
5-1
5-2
5-3
5-4 - out (sum is 9)
5-6
6-1
6-2
6-3 - out (sum is 9)
6-4
6-5

total 26.

answer is C
Re: Ed throws a blue die and a red die. How many combinations are there in   [#permalink] 07 Apr 2017, 15:29
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Ed throws a blue die and a red die. How many combinations are there in

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