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# Eight identical machines can produce 360 aluminum cans per

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Manager
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Eight identical machines can produce 360 aluminum cans per [#permalink]

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07 Jun 2011, 14:31
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Question Stats:

92% (00:59) correct 8% (01:01) wrong based on 408 sessions

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Eight identical machines can produce 360 aluminum cans per hour. If all of the machines work at the same constant rate, how many cans could 5 such machines produce in 3 hours?

A. 675
B. 750
C. 1,800
D. 5,900
E. 7,500
[Reveal] Spoiler: OA

Last edited by Bunuel on 21 Sep 2012, 04:42, edited 1 time in total.
Renamed the topic.

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Manager
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Re: From MitDavidDv: Problem Solving Question-Rate [#permalink]

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07 Jun 2011, 14:38
8 machines/ 360 cans = 5 machines/ x cans
8x= 1800
x=225

(225)(3 hours)= 675 cans. The answer is A.

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Re: From MitDavidDv: Problem Solving Question-Rate [#permalink]

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08 Jun 2011, 03:16
1
KUDOS
Hi, if 8 machines make 360 then 5 would make
8:360
5:x
X= 225
so in 3 hours it would be 225*3=675

Posted from GMAT ToolKit

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Re: From MitDavidDv: Problem Solving Question-Rate [#permalink]

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10 Jun 2011, 22:26
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Re: From MitDavidDv: Problem Solving Question-Rate [#permalink]

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21 Sep 2012, 04:38
Hi Everyone,

I have a question, can we solve this question using the W=RT method ? Please reply.. if yes.. please tell me as i am getting wrong answer if i go that way !!

Thanks

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Re: From MitDavidDv: Problem Solving Question-Rate [#permalink]

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21 Sep 2012, 04:47
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KUDOS
Expert's post
154238 wrote:
Hi Everyone,

I have a question, can we solve this question using the W=RT method ? Please reply.. if yes.. please tell me as i am getting wrong answer if i go that way !!

Thanks

Eight identical machines can produce 360 aluminum cans per hour. If all of the machines work at the same constant rate, how many cans could 5 such machines produce in 3 hours?

A. 675
B. 750
C. 1,800
D. 5,900
E. 7,500

(rate of one machine)*(number of machines)*(time)=(work done) --> (rate of one machine)*8*1=360 --> (rate of one machine)=45 cans per hour.

Now, 5 such machines in 3 hours can produce (rate of one machine)*(number of machines)*(time)=45*5*3=675 cans.

Hope it's clear.
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Re: Eight identical machines can produce 360 aluminum cans per [#permalink]

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21 Sep 2012, 05:06

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Re: Eight identical machines can produce 360 aluminum cans per [#permalink]

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15 Nov 2012, 04:16
$$\frac{8}{M}=\frac{360cans}{1hr}==>\frac{1}{M} = 45cans/1hr$$

Calculate 5 machines doing work in 3 hours.
$$W=(5)(\frac{45cans}{1hr})(3hrs)==>W=675cans$$
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Re: Eight identical machines can produce 360 aluminum cans per [#permalink]

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16 Jan 2016, 10:17
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Re: Eight identical machines can produce 360 aluminum cans per [#permalink]

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05 Jul 2016, 06:49
MitDavidDv wrote:
Eight identical machines can produce 360 aluminum cans per hour. If all of the machines work at the same constant rate, how many cans could 5 such machines produce in 3 hours?

A. 675
B. 750
C. 1,800
D. 5,900
E. 7,500

rt=w
8(rt)=360

rt=45

t=1 ===> r=45

rt=w

r=45
t=3

n=5

5rt=5(45*3)=675

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Re: Eight identical machines can produce 360 aluminum cans per [#permalink]

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26 Jun 2017, 16:29
Rate of each machine $$= \frac{360}{8}= 45$$
Rate of 5 machines $$= 45*5 = 225$$
Total cans from 5 machines in 3 hrs = Rate * time = 225*3

At this point the units digit comes out as 5 and I am a stickler for time. The only answer is A.
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Re: Eight identical machines can produce 360 aluminum cans per [#permalink]

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29 Jun 2017, 15:50
Eight identical machines can produce 360 aluminum cans per hour. If all of the machines work at the same constant rate, how many cans could 5 such machines produce in 3 hours?

8 Machines - 360 Cans/Hour

1 Machine = 45 Cans/Hour

5 Machines in 3 Hours $$= 45 * 5 * 3 = 675$$

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Re: Eight identical machines can produce 360 aluminum cans per   [#permalink] 29 Jun 2017, 15:50
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