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# Eleven books consisting of 5 financial management, 4 marketi

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Intern
Joined: 25 Jan 2013
Posts: 24
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Kudos [?]: 45 [0], given: 11

Eleven books consisting of 5 financial management, 4 marketi [#permalink]

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30 Jan 2013, 23:54
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Difficulty:

55% (hard)

Question Stats:

63% (03:20) correct 37% (01:59) wrong based on 82 sessions

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Eleven books consisting of 5 financial management, 4 marketing management and 2 system management are placed on a shelf at random order. What is the probability that the books of each kind are all together.

A. 1/1155
B. 1/1255
C. 1/1355
D. 1/1455
E. 1/1555
[Reveal] Spoiler: OA

Last edited by Bunuel on 31 Jan 2013, 04:10, edited 1 time in total.
RENAMED THE TOPIC.
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Joined: 02 Sep 2009
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Kudos [?]: 105766 [2] , given: 11581

Re: Eleven books consisting of 5 financial management, 4 marketi [#permalink]

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31 Jan 2013, 04:25
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Expert's post
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antoxavier wrote:
Eleven books consisting of 5 financial management, 4 marketing management and 2 system management are placed on a shelf at random order. What is the probability that the books of each kind are all together.

A. 1/1155
B. 1/1255
C. 1/1355
D. 1/1455
E. 1/1555

(Probability of an event) = (Favorable) / (Total)

The total number of ways to arrange 11 books in a row is 11!.

3 groups of books: financial management (F), marketing management (M) and system management (S), can be arranged in 3! ways: FMS, FSM, MFS, MSF, SFM, and SMF (this way all the books of each kind will be together). Now, books in F itself can be arranged in 5! ways, in M in 4! ways and in S in 2! ways. Hence, the total number of ways to arrange books so that books of each kind are together is 3!*5!*4!*2!.

P = (3!*5!*4!*2!) / 11! = 1/1155.

Hope it's clear.

P.S. P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to the rule #3 (the name of a topic MUST be the first 40 characters (~the first two sentences) of the question).
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Re: Eleven books consisting of 5 financial management, 4 marketi [#permalink]

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25 Aug 2013, 21:38
Since the denominator will be 11! . And there is no way to divide 11 from numerator and denominator. Use a multiple of 11 in the denominator only answer A

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Re: Eleven books consisting of 5 financial management, 4 marketi [#permalink]

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15 Dec 2014, 04:58
Hello from the GMAT Club BumpBot!

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Eleven books consisting of 5 financial management, 4 marketi [#permalink]

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28 Feb 2016, 11:01
I used a different approach..
total number of possible arrangements: 11!/5!4!2! = 6930.
only 1155 is a multiple of 6930.

A.
Eleven books consisting of 5 financial management, 4 marketi   [#permalink] 28 Feb 2016, 11:01
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