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Emily and Tammi must both run from point A to reach the finish line, w
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Updated on: 25 Oct 2015, 05:48
Question Stats:
66% (02:55) correct 34% (02:34) wrong based on 166 sessions
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Emily and Tammi must both run from point A to reach the finish line, which stretches from the origin to point B, but they have to run on two different paths, where Emily will end up 4 yards away from Tammi on the finish line. If Tammi ran a total of 10 yards, how many yards more did Emily run than Tammi? A. 2 B. \(4\sqrt{2}−10\) C. \(6\sqrt{5}−10\) D. \(4\sqrt{2}−8\) E. \(6\sqrt{5}\) Attachment:
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Originally posted by shasadou on 24 Oct 2015, 05:32.
Last edited by Bunuel on 25 Oct 2015, 05:48, edited 1 time in total.
Edited the question.



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Emily and Tammi must both run from point A to reach the finish line, w
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02 Dec 2015, 00:12
Hi everyone, I took close to 4 minutes to solve this. Are there any suggestions on how I can halve my time spent in a question like this? here's how i solved this question.. we know that Tammi ran 10 yards (t= 10) and we do not know how far Emily (e) ran. question: e  t = ? 1) using the Pythagorean theorem, I solved for x. 10^2 = 6^2 + x^2 x = \(\sqrt{64}\) 2) next, I solved for the distance that Emily ran, e. [given Emily will end up 4 yards away from Tammi on the finish line, the base of the triangle is \(\sqrt{64}\)+4] e^2 = 6^2 + (\(\sqrt{64}\)+4)^2 e^2 = 36 + (\(\sqrt{64}\)+4)(\(\sqrt{64}\)+4) e^2 = 36 + 64 + 4\(\sqrt{64}\) + 4\(\sqrt{64}\) + 16 e^2 = 116 + 8\(\sqrt{64}\) e^2 = 116 + 8(8) e^2 = 180 e =\(\sqrt{180}\) 3) now that I've obtained both e and t, time to plug it into the original question, e  t = ? \(\sqrt{180}\)  10 =\(\sqrt{36*5}\)  10 = 6\(\sqrt{5}\)  10



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Re: Emily and Tammi must both run from point A to reach the finish line, w
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13 May 2016, 09:19
Foxed , marked E ; did not realize that the question asked for how much more ! A classic GMAT trap !
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Re: Emily and Tammi must both run from point A to reach the finish line, w
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01 Aug 2016, 02:31
whitehalo wrote: Hi everyone, I took close to 4 minutes to solve this. Are there any suggestions on how I can halve my time spent in a question like this? here's how i solved this question.. we know that Tammi ran 10 yards (t= 10) and we do not know how far Emily (e) ran. question: e  t = ? 1) using the Pythagorean theorem, I solved for x. 10^2 = 6^2 + x^2 x = \(\sqrt{64}\)2) next, I solved for the distance that Emily ran, e. [given Emily will end up 4 yards away from Tammi on the finish line, the base of the triangle is \(\sqrt{64}\)+4] e^2 = 6^2 + (\(\sqrt{64}\)+4)^2 e^2 = 36 + (\(\sqrt{64}\)+4)(\(\sqrt{64}\)+4) e^2 = 36 + 64 + 4\(\sqrt{64}\) + 4\(\sqrt{64}\) + 16 e^2 = 116 + 8\(\sqrt{64}\) e^2 = 116 + 8(8)e^2 = 180 e =\(\sqrt{180}\) 3) now that I've obtained both e and t, time to plug it into the original question, e  t = ? \(\sqrt{180}\)  10 =\(\sqrt{36*5}\)  10 = 6\(\sqrt{5}\)  10The approach is correct. I would only simply the highlighted section further to make it \(x = \sqrt{64} = 8\) That would in in turn simplify the calculation for e. \(e^2 = 6^2 + (8+4)^2\) \(e^2 = 36 + (12)^2\) \(e^2 = 36 + 144\) \(e^2 = 180\) \(e = \sqrt{180}\)



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Emily and Tammi must both run from point A to reach the finish line, w
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17 Jun 2017, 03:56
shasadou wrote: Emily and Tammi must both run from point A to reach the finish line, which stretches from the origin to point B, but they have to run on two different paths, where Emily will end up 4 yards away from Tammi on the finish line. If Tammi ran a total of 10 yards, how many yards more did Emily run than Tammi? A. 2 B. \(4\sqrt{2}−10\) C. \(6\sqrt{5}−10\) D. \(4\sqrt{2}−8\) E. \(6\sqrt{5}\) Attachment: The attachment Geometry_Img67.png is no longer available The hidden inference in this question is that distance Tammi travels represents a pythagorean triplet triangle ( 6 8 10) there's really only two ways that Tammi could have traveled 10 yards she could go straight down from (0,6) to the origin (0,0) and then travel to (4,0); however, if this was done then the distance Emily runs would actually be the same as Tammie and thus false. Therefore, the distance Tammi runs represents the hypotenuse of the triangle  10. If the hypotenuse of the triangle is 10 then the x coordinate of Tammi's current position is 8 as in (8,0). And because Emily must be 4 yards away, Emily's coordinate is (12,0). From here apply the distance formula Emily's distance from her current position and Point A and then subtract it by the distance Tammi traveled 10 yards. Thus "C"
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Emily and Tammi must both run from point A to reach the finish line, w
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Updated on: 19 Jul 2017, 03:08
shasadou wrote: Emily and Tammi must both run from point A to reach the finish line, which stretches from the origin to point B, but they have to run on two different paths, where Emily will end up 4 yards away from Tammi on the finish line. If Tammi ran a total of 10 yards, how many yards more did Emily run than Tammi? A. 2 B. \(4\sqrt{2}−10\) C. \(6\sqrt{5}−10\) D. \(4\sqrt{2}−8\) E. \(6\sqrt{5}\) Attachment: Geometry_Img67.png Let the origin be O. Let the position of Tammi shown in diagram be T and the position of Emily shown is diagram be E. So, OA =6 AT = 10 ( Tammi ran a total of 10 yards) From right angled triangle OAT OT =\(\sqrt{(10^2  6^2)}\) = 8 (we can also figure it out from pythagorean triplet 3,4,5 or 6,8,10 So, OE = OT + TE = 8 + 4 = 12 AE = \(\sqrt{(OA^2 + OE^2)} = \sqrt{6^2 + 12 ^2} = \sqrt{36+144} =\sqrt{180} = 6\sqrt{5}\) Emily ran \(6\sqrt{5}  10\) yards more than Tammi. Answer C
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Originally posted by shashankism on 19 Jul 2017, 02:16.
Last edited by shashankism on 19 Jul 2017, 03:08, edited 2 times in total.



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Re: Emily and Tammi must both run from point A to reach the finish line, w
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19 Jul 2017, 02:26
shashankism wrote: shasadou wrote: Emily and Tammi must both run from point A to reach the finish line, which stretches from the origin to point B, but they have to run on two different paths, where Emily will end up 4 yards away from Tammi on the finish line. If Tammi ran a total of 10 yards, how many yards more did Emily run than Tammi? A. 2 B. \(4\sqrt{2}−10\) C. \(6\sqrt{5}−10\) D. \(4\sqrt{2}−8\) E. \(6\sqrt{5}\) Attachment: Geometry_Img67.png Let the origin be O. So, OA =6 AT = 10 ( Tammi ran a total of 10 yards) From right angled triangle OAT OT =\sqrt{(10^2  6^2)} = 8 (we can also figure it out from pythagorean triplet 3,4,5 or 6,8,10 So, OE = OT + TE = 8 + 4 = 12 AE = \sqrt{(OA^2 + OE^2)} = \sqrt{6^2 + 12 ^2} = \sqrt{36+144} =\sqrt{180} = 6\sqrt{5} Emily ran 6\sqrt{5}  10 yards more than Tammi. Answer CVery simple and straightforward approach, thank you.
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Re: Emily and Tammi must both run from point A to reach the finish line, w
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21 Jul 2017, 01:58
TimeTraveller wrote: Very simple and straightforward approach, thank you.
That's the beauty of solving questions in GMAT Club w, we get to know the shortest and the best possible approach to solve a problem. Many people contribute to the solution and hence we get the best one ..
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