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# Equal amount of water were poured into two empty jars of

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Joined: 04 Jul 2010
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Equal amount of water were poured into two empty jars of  [#permalink]

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Updated on: 24 Jun 2013, 02:58
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25% (medium)

Question Stats:

70% (01:25) correct 30% (01:35) wrong based on 1163 sessions

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Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

A. 1/7
B. 2/7
C. 1/2
D. 7/12
E. 2/3

Originally posted by leafsrule99 on 11 Aug 2010, 13:17.
Last edited by Bunuel on 24 Jun 2013, 02:58, edited 3 times in total.
Edited the question and added the OA
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11 Aug 2010, 16:21
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Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

A. 1/7
B. 2/7
C. 1/2
D. 7/12
E. 2/3

Shortcut solution:

Some amount of water made bigger jar 1/4 full, then the same amount of water (stored for a while in smaller jar) were added to bigger jar, so bigger jar is 1/4+1/4=1/2 full.

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Re: Equal amounts of water were poured into two empty jars of  [#permalink]

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06 Dec 2011, 23:12
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Equal amounts of water were poured into both jars and this made big jar as 1/4 full then same amount from smaller jar is poured . It will make 2*(1/4)= 1/2 full
##### General Discussion
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10 Feb 2011, 19:15
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1/2 seems straight forward. If x amount of water fills up the jar upto 1/4th of its capacity, 2x will fill up 1/2.
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11 Feb 2011, 06:14
2
My take on this (although Mavens like Bunuel can always expound in 2 lines)

Let v be the volume of water added to both :

v = x/4

v = y/3

x = 4v (total capacity of larger jar)

y = 3v (total capacity of smaller jar)

So v is added again to larger jar, hence total water = v+v
2v
--- = 1/2
4v
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Re: Equal amounts of water were poured into two empty jars of  [#permalink]

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04 Dec 2011, 10:29
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Capacity larger jar = x
Let 20 litters water poured into each jar
so x*1/4 = 20
x = 80
Total water of larger jar after pouring the water of smaller jar = 20+20 = 40
40/80 = 1/2
Ans. C
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Re: Equal amount of water were poured into two empty jars of  [#permalink]

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04 May 2013, 04:52
Hi Experts

Let the capacity of both jug X(small) & Y(big)
After pouring water... capacity of water both jug x/4 and y/3... as given x/4=y/3 so x=4y/3

now given smaller jug water poured into bigger made the equ- x/4+y/3=>3x+4y/12..putting x=4y/3...we got 2y/3 which mean 2/3 rd of y

Rgds
Prasannajeet
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Re: Equal amount of water were poured into two empty jars of  [#permalink]

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04 May 2013, 05:58
prasannajeet wrote:
Hi Experts

Let the capacity of both jug X(small) & Y(big)
After pouring water... capacity of water both jug x/4 and y/3... as given x/4=y/3 so x=4y/3

now given smaller jug water poured into bigger made the equ- x/4+y/3=>3x+4y/12..putting x=4y/3...we got 2y/3 which mean 2/3 rd of y

Rgds
Prasannajeet

x/4=y/3, thus x is larger jar and y is smaller jar.
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Re: Equal amount of water were poured into two empty jars of  [#permalink]

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01 Dec 2014, 00:01
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First determine which is the big one?

$$\frac{1}{4} th$$ is the big container as equal quantities of water poured made it "less full"

Same quantity of water added twice, so multiply by 2

$$2 * \frac{1}{4} = \frac{1}{2}$$

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Re: Equal amount of water were poured into two empty jars of  [#permalink]

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04 Jan 2015, 06:41
1
I actually drew the jars to solve it, without calculating anything...

Just to give you a good laugh, I will describe how:

So, I first created one jar, and marked its 1/4th and 1/3rd. This showed me that if these were 2 jars, the one filled up to its 1/4th must be the bigger one.

Then I just drew 2 same jars, next to eac other, and marked 1/4th in one and 1/3rd in the other. I pulled the line that marked the 1/4th of one jar on the second jar, and saw that there was only a little it lower than the 1/3rd. The I realised that if I moved the rest to jar one, it would be filled half way... So, 1/2.

Mind that I am a psychologist... Sometimes, it is easier for me not to do the math!
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Re: Equal amount of water were poured into two empty jars of  [#permalink]

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05 Jan 2018, 09:05
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leafsrule99 wrote:
Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

A. 1/7
B. 2/7
C. 1/2
D. 7/12
E. 2/3

Let’s say that one jar has a capacity of 16 liters and the other, 12 liters. So, when equal parts water are poured into each jar, one jar has 4 liters and the other has 4 liters. When the contents of the small jar (4 liters from the 12-liter jar) are poured into the larger jar (4 litters in the 16-liter jar), the larger jar is now 8/16 = 1/2 full.

Alternate Solution:

Consider only the larger jar. When the first amount of water is poured into it, the jar becomes ¼ full. Now, a second amount of water, which is actually equal to the first amount, is poured into the larger jar. This second amount of water is also equivalent to ¼ of the jar’s capacity. Thus, the jar is now ¼ + ¼ = ½ full.

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Re: Equal amounts of water were poured into the two empty jars  [#permalink]

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Re: Equal amounts of water were poured into the two empty jars   [#permalink] 10 Oct 2019, 03:14