It is currently 24 Jun 2017, 00:13

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Equation |x/2|+|y/2|=5 encloses a certain region on the

Author Message
Manager
Joined: 18 Mar 2004
Posts: 50
Equation |x/2|+|y/2|=5 encloses a certain region on the [#permalink]

### Show Tags

03 Apr 2007, 15:06
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Equation |x/2|+|y/2|=5 encloses a certain region on the coordinate plane. what is the are of this region?

20
50
100
200
400

Manager
Joined: 02 Jan 2007
Posts: 208

### Show Tags

03 Apr 2007, 15:27
100 for me... It's a long wild shot.
we can get
|x| + |y| = 10

this will be true if the co-ordinates of the enclosed area are
5,5
5,-5
-5,-5 &
-5,5

distance works out to 10
and 10*10 = 100

However the co-ordinates could just as easily be
6,4 or
7,-3 etc.,

haven't checked these possibilities. I think this should be sufficient ...but again I haven't checked... the shapes coming out are too weird for me to calculate their areas.
Director
Joined: 18 Jul 2006
Posts: 524

### Show Tags

03 Apr 2007, 15:54
Should be D.
In Ist quad x+y = 10 => x intersect (0,10), y intersect (10,0) +> area of triangle => 1/2*10*10 => 50

Similarly calculate of triangles in other quadrants.

Total area = 50+50+50+50 => 200.
Manager
Joined: 18 Mar 2004
Posts: 50

### Show Tags

03 Apr 2007, 15:59
http://www.gmatclub.com/phpbb/viewtopic ... =challenge

Director
Joined: 14 Jan 2007
Posts: 774

### Show Tags

03 Apr 2007, 19:18
my approach is -

Line x/a + y/b = 1 where a and b are intercepts on x and y axis respectively.
given line |x|/10 + |y|/10 = 1

Exploring all possible values the area of the triangle = 4 * (1/2 *10 *10) =200
Director
Joined: 26 Feb 2006
Posts: 899

### Show Tags

03 Apr 2007, 23:58
fmeinsen wrote:
Equation |x/2|+|y/2|=5 encloses a certain region on the coordinate plane. what is the are of this region?

20
50
100
200
400

I liked the question. probably the question meant the maximum area.

since |x/2|+|y/2| = 5
|x|+|y| = 10

we donot know the values of x and y. they could be +ve or -Ve. if so, x can be a minimum of -10 and a maximum of 10 and do does y. therefore,

x = -10 or 10
y = -10 or 10

if we draw a pricture, it becomes a square with a side of 10-(-10) = 20.
then the area = 20 x 20 = 400.
Re: Coordinate Geometry   [#permalink] 03 Apr 2007, 23:58
Display posts from previous: Sort by