Check GMAT Club Decision Tracker for the Latest School Decision Releases

It is currently 26 May 2017, 22:36


GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

for You

we will pick new questions that match your level based on your Timer History

Your Progress

every week, we’ll send you an estimated GMAT score based on your performance


we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.


Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

ETS: Circle

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Joined: 06 Aug 2004
Posts: 4
Followers: 0

Kudos [?]: 0 [0], given: 0

ETS: Circle [#permalink]

Show Tags

New post 15 Sep 2004, 10:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

could n't figure this out...
pls help

Doc1.doc [35 KiB]
Downloaded 59 times

To download please login or register as a user

Senior Manager
Senior Manager
Joined: 05 Feb 2004
Posts: 290
Location: USA
Followers: 1

Kudos [?]: 5 [0], given: 0


Show Tags

New post 15 Sep 2004, 11:25
I did a silly mistake previously..hence edited!!
basically, 2 squares are formed......two sides of larger square are 80*2 = 160 cm in lengtjh. Similarly, 2 sides of smaller one are 60 *2 = 120 cm in length. Total is 280 cm. Now add 3/4th of the 2 circumferemnces as well:
Big circlr: 3/4*2* Pi*80 = 120Pi
Small circle: 3/4*2*pi*60 = 90Pi

Total = 120pi+90pi+280 = B!!
Joined: 18 Jun 2004
Posts: 103
Location: san jose , CA
Followers: 2

Kudos [?]: 88 [0], given: 0


Show Tags

New post 16 Sep 2004, 03:51
B it is ,

you don't need to complete calculation if you see there is some cord which is connecting the two discs and and two sectors are left free without cord .

calculate disc 1 = 270/360 * 2* pi*80
cl . disc 2 - 270/360 *2 * pi* 60

= 90pi + 120 pi = 210 pi + the extra length
if look at the choice there is only once choice which is 210 oi + extra B
so the rest you need not calculate .

let me know if their is any flaw in my reasoning .

---- Hero never chooses Destiny
Destiny chooses Him ......

User avatar
Joined: 16 Jun 2004
Posts: 892
Followers: 3

Kudos [?]: 63 [0], given: 0


Show Tags

New post 16 Sep 2004, 04:31
My approach was
1. the staight tangent lines connecting the circle = 140+140 = 280.
2. It has to be 280+some Pi stuff (because portion of the circumference of the two circles also need to be added - which would invariably be a pi something).
3. We are now left with B and E options.
4. E is too big - why? 2(pi)(r) of both the circles = 280pi. Surely we need smaller than that (because the cord does not wound the entire circle and only portion of it) and we have only one option in our shortlist and that is B.

We can calculate B for sure if we have time as already outlined by CBRf3 and Rahul.
  [#permalink] 16 Sep 2004, 04:31
Display posts from previous: Sort by

ETS: Circle

  post reply Question banks Downloads My Bookmarks Reviews Important topics  

GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.