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# exponent problem

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Intern
Joined: 20 Mar 2006
Posts: 3

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23 Mar 2006, 20:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi could someone just show out the work for this one?

x = 10^100, x^x=10^k, k=?

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Director
Joined: 10 Oct 2005
Posts: 713

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23 Mar 2006, 23:08
x = 10^100, x^x=10^k, k=?
substitute x with 10^100--->(10^100)^(10^100)=10^k since the base is same 10 and 10 we get k=100^(10^100)
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Intern
Joined: 20 Mar 2006
Posts: 3

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25 Mar 2006, 10:42
The answer given to this was k=102

so 10^102. For some reason I am having a hard time simplifying that

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SVP
Joined: 14 Dec 2004
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25 Mar 2006, 10:53
k = 10^102

x^x = (10^100)^(10^100)

= 10^(100*(10^100))
= 10^((10^2)*(10^100))
= 10^(10^102) = 10^k

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25 Mar 2006, 10:53
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