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Find an integer M. (1) M^M=M^3 (2) =1

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New post 22 May 2003, 00:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Find an integer M.

(1) M^M=M^3
(2) [M^3]=1

:kill

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New post 22 May 2003, 01:02
again a classic.......would go with E

either u had the best sex of your life or u just met God..... :lol: :lol: :wink: :wink: :wink:

those are the only two reasons i can think of for these problems that you created :wink: :wink: :idea: :idea:

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New post 22 May 2003, 01:16
You are right; it is E.
I have neither met God, nor have I had great sex.
This is because I have just been granted admin rights! :done

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New post 22 May 2003, 01:21
admin rights???????

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New post 22 May 2003, 01:27
To some degree of course. I can add new smiles and erase old ones. A cool job, isn't it?

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New post 22 May 2003, 01:31
thanks for the smiles.........they are :cool

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New post 22 May 2003, 01:36
There is a great Russian site: http://smiles.elze.ru/index_eng.htm
The best collection of smiles in the net.

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New post 22 May 2003, 11:50
Can someone explain why it's E?

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New post 22 May 2003, 18:37
from statement 1

(-1)^-1 = -1 & (-1)^3 = -1
&
(1)^1 = 1 & (1)^3 =1

therefore M = 1 or -1

from statment 2

[(-1)^3] = 1
&
[(1)^3] = 1

therefore M = 1 or -1

from both statements together we cannot say whether M =1 or -1

therefore answer is E

hope that helps

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New post 22 May 2003, 21:04
brstorewala wrote:
from statment 2
[(-1)^3] = 1


But [(-1)^3] = -1, does it not???

That simply leaves [(1)^3] = 1...so isn't statement 2 sufficient?

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New post 22 May 2003, 21:09
[...] is modulus sign......the sign is always positive

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New post 22 May 2003, 22:02
brstorewala wrote:
from statement 1

(-1)^-1 = -1 & (-1)^3 = -1
&
(1)^1 = 1 & (1)^3 =1

therefore M = 1 or -1

from statment 2

[(-1)^3] = 1
&
[(1)^3] = 1

therefore M = 1 or -1

from both statements together we cannot say whether M =1 or -1

therefore answer is E

hope that helps



The trick is that (1) has THREE solutions! 1, -1, and 3 :boxer2

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New post 22 May 2003, 22:23
stolyar wrote:
brstorewala wrote:
from statement 1

(-1)^-1 = -1 & (-1)^3 = -1
&
(1)^1 = 1 & (1)^3 =1

therefore M = 1 or -1

from statment 2

[(-1)^3] = 1
&
[(1)^3] = 1

therefore M = 1 or -1

from both statements together we cannot say whether M =1 or -1

therefore answer is E

hope that helps



The trick is that (1) has THREE solutions! 1, -1, and 3 :boxer2



ohhhhhhh yessss.....luckily i got the answer correct......... :roll: :wink:

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New post 22 May 2003, 22:53
It is the first time I have caught you. Even so, you have managed to safely escape. :-D

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New post 26 May 2003, 00:39
what is 0^0..is this another possible solution from 1?

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New post 26 May 2003, 00:53
skoper wrote:
what is 0^0..is this another possible solution from 1?



I think we 've decided that 0^0 is undefined; I will ask the people in charge about it, but so far, the unanimous decision has been UNDEFINED


-=-

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New post 26 May 2003, 00:56
bb wrote:
skoper wrote:
what is 0^0..is this another possible solution from 1?



I think we 've decided that 0^0 is undefined; I will ask the people in charge about it, but so far, the unanimous decision has been UNDEFINED


-=-


i punched this into my windows :) calculator right now

answer = 1

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New post 26 May 2003, 01:01
skoper wrote:
bb wrote:
skoper wrote:
what is 0^0..is this another possible solution from 1?



I think we 've decided that 0^0 is undefined; I will ask the people in charge about it, but so far, the unanimous decision has been UNDEFINED


-=-


i punched this into my windows :) calculator right now

answer = 1




The funny thing is that you are right :lol:

and nobody did it!

I think you just deserved a premium membership just for that.

I can't stop laughing.


-=-=

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New post 26 May 2003, 01:02
Or maybe it is Evil Microsoft?

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New post 26 May 2003, 01:03
it is indeed evil Microsoft - my Sharp Scientific Calculator gave Error code 2, whatever that means.

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