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# Find integer S. (1) S!=S (2) S!=1

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SVP
Joined: 03 Feb 2003
Posts: 1604
Find integer S. (1) S!=S (2) S!=1 [#permalink]

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22 May 2003, 01:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Find integer S.

(1) S!=S
(2) S!=1
Manager
Joined: 28 Feb 2003
Posts: 100

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22 May 2003, 01:30
C?

....very good questions.......great......
SVP
Joined: 03 Feb 2003
Posts: 1604

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22 May 2003, 01:41
Your perfectionism scares me. C is correct.
I feel I have to create something more difficult.
As far as I remember, you have done no mistake while dealing with my problems. It is the all-time record.

I do mistakes while dealing with yours.
Intern
Joined: 15 Apr 2003
Posts: 23

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02 Jun 2003, 11:19
Can someone explain this to me?
If s!=1, doesnt s=1?

Manager
Joined: 25 May 2003
Posts: 54

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02 Jun 2003, 16:07
from 1) answers are 1 and 2

from 2) answers are 0 and 1

don't forget 0! also equals 1

therefore both are needed, therefore C
Senior Manager
Joined: 03 Nov 2005
Posts: 384
Location: Chicago, IL

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16 Dec 2005, 22:10

1. Insufficient.

2. 0!=1, so S=1

B stands
_________________

Hard work is the main determinant of success

Senior Manager
Joined: 03 Nov 2005
Posts: 384
Location: Chicago, IL

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16 Dec 2005, 22:13
I got you, stupid mistakes. To be honest, they're killing me the most.

(1) 0!=1 and 1!=1 So S=1 or S=0

(1) and (2) S=1

C.
_________________

Hard work is the main determinant of success

SVP
Joined: 28 May 2005
Posts: 1707
Location: Dhaka

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17 Dec 2005, 02:45
is S! = S it got to be 1

because 1! = 1 and 0! =1

now it is not zero because 0! is not equal to zero.

on the other hand statement 2) says S! = 1, so s can be 0 or 1, so it is insufficient.

_________________

hey ya......

Director
Joined: 09 Jul 2005
Posts: 591

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17 Dec 2005, 04:15
numlock31 wrote:
Can someone explain this to me?
If s!=1, doesnt s=1?

0!=1 and 1!=1

From (1) we know that S=1 or S=2; From (2) we know that S=0 or S=1; From (1) and (2) we know that S=1.
Senior Manager
Joined: 05 Oct 2005
Posts: 485

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19 Dec 2005, 18:05
nakib77 wrote:
is S! = S it got to be 1

because 1! = 1 and 0! =1

now it is not zero because 0! is not equal to zero.

on the other hand statement 2) says S! = 1, so s can be 0 or 1, so it is insufficient.

I think you are forgetting that 2! = 2, which gives 2 values for st 1)
st 2) gives 0 or 1..

together, only 1 is common, hence C.
19 Dec 2005, 18:05
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