souvonik2k wrote:

Harshgmat wrote:

Find the area of common portion when two circles intersect as shown below

A) Distance between the centers of two circle is \(2\sqrt{2}\).

B) Arcs in common portion subtend 90 degree angle at the centers of respective circles.

S1 - Circles may not be of same radius.

Insufficient.

S2 - Means circles have same radius, but no value given.

Insufficient.

Combining, since Distance between the centers of two circle is \(2\sqrt{2}\) and the circles are of same radius.

We can find the radius, subsequently we can find the area of common portion.

Sufficient.

Answer C.

Please provide the OA.Hi

souvonik2k,

After combining the above two statements also, we will get two values for r. Please correct me if I am wrong.

Scenario I: The two common arcs may pass through each other centres. Hence, \(r = 2\sqrt{2}.\)

Scenario II: The two arcs may not pass through each other centres, Here, \(r # 2\sqrt{2}.\)

Hence, E.

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