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Find the length of the common chord of two intersecting circles of rad

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Find the length of the common chord of two intersecting circles of rad  [#permalink]

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New post 01 Jan 2020, 10:00
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Q. Find the length of the common chord of two intersecting circles of radii 15 cm and 20 cm, given that the distance between the centers of the circles is 25cm.

A. 9
B. 18
C. 12
D. 24
E. 15
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Find the length of the common chord of two intersecting circles of rad  [#permalink]

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New post 01 Jan 2020, 16:53
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AC=15cm; BC=20cm; and AB=25cm

We can notice that (15,20,25) is a pythagorean triplet; hence, ACB is a right angle triangle.

Also, Line from the center perpendicularly bisects the chord.

Area of triangle ABC= \(\frac{1}{2}*AC*BC= \frac{1}{2}*CO*AB\)

CO= \(\frac{AC*BC}{AB}= \frac{15*20}{25}=12\)

CD= 2*12=24


PiyushPanda1 wrote:
Q. Find the length of the common chord of two intersecting circles of radii 15 cm and 20 cm, given that the distance between the centers of the circles is 25cm.

A. 9
B. 18
C. 12
D. 24
E. 15

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Re: Find the length of the common chord of two intersecting circles of rad  [#permalink]

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New post 02 Jan 2020, 10:00
This is bit tricky problem but fortunately got correct as I saw the Pythagoras triplet & chose the correct answer, I.e. 24.

@experts or moderators,
Still, I need to find any other alternative visual approach. Is it possible?

Posted from my mobile device
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Find the length of the common chord of two intersecting circles of rad  [#permalink]

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New post 02 Jan 2020, 10:38
Raxit85,

This can also be solved by using variables as follows: Refer to the figure/attachment by nick1816 for below explanation.

Let AO = x. So, BO = 25 - x.
As we know, when two circles intersect, the common chord is perpendicular to the line joining the centers of the circles.
Hence, CD is perpendicular to AB.

So, \(CO^2\) = \(AC^2\) - \(AO^2\) = \(BC^2\) - \(BO^2\).
We get, \(15^2\) - \(x^2\) = \(20^2\) - \((25-x)^2\), which gives x = 9.

Now, \(OC^2\) = \(15^2\) - \(9^2\) = 225 - 81 = 144
So, OC = 12.

As we know OC = OD, OD = 12.
CD = OC + OD = 12 + 12 = 24.

Hope this help was helpful!
GMAT Club Bot
Find the length of the common chord of two intersecting circles of rad   [#permalink] 02 Jan 2020, 10:38
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