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Re: Find the square of the length of the shortest path that can be drawn [#permalink]
nick1816 wrote:
The shortest path between 2 points in 2-Dimension is always a straight line. The reflected part is equal to the distance between (6,3) and (-2,-8)
Square of distance= (6-(-2))^2+(3-(-8))^2= 8^2+11^2=185
ManjariMishra wrote:
Can anybody please explain the solution

Posted from my mobile device


nick1816 - I don't fully understand. How do we know the distance between (6,3) and (-2,-8) is the same as the reflected portion? Thanks in advance.
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Find the square of the length of the shortest path that can be drawn [#permalink]
The shortest path between 2 points in 2-Dimension is always a straight line
1. The shortest vertical distance between point A and B,if the path have to touch x axis, is equal to |0-3|+|8-0|=11
2. The shortest horizontal distance between point A and B,if the path have to touch y axis, is equal to |0-6|+|2-0|=8

Square of shortest distance= 11^2 + 8^2= 185


fogarasm wrote:
nick1816 wrote:
The shortest path between 2 points in 2-Dimension is always a straight line. The reflected part is equal to the distance between (6,3) and (-2,-8)
Square of distance= (6-(-2))^2+(3-(-8))^2= 8^2+11^2=185
ManjariMishra wrote:
Can anybody please explain the solution

Posted from my mobile device


nick1816 - I don't fully understand. How do we know the distance between (6,3) and (-2,-8) is the same as the reflected portion? Thanks in advance.

Originally posted by nick1816 on 25 May 2019, 08:39.
Last edited by nick1816 on 26 May 2019, 13:16, edited 1 time in total.
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Re: Find the square of the length of the shortest path that can be drawn [#permalink]
Bunuel could you please help in this question ?
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Re: Find the square of the length of the shortest path that can be drawn [#permalink]
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