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Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7 B. 5/7 C. 4/7 D. 3/7 E. 2/7

There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.

These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case.

The probability of that is 2/7.

Answer: E.

Hope it's clear.

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Re: Find the probability that a leap year selected at random [#permalink]

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25 Jul 2014, 21:19

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Re: Find the probability that a leap year selected at random [#permalink]

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20 Jun 2016, 19:52

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Find the probability that a leap year selected at random [#permalink]

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22 Mar 2017, 02:27

Any given year will always have 52 complete weeks. So 52 Sundays will always be there in any year.

A leap year has 366 days. 52 weeks = 52*7=364 days

So we have 2 extra days apart from 52 weeks.

These 2 days can be (Saturday, Sunday), (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday,Thursday), (Thursday, Friday), (Friday, Saturday).

For the year to have 53 Sundays, the 2 days must be either (Saturday, Sunday) or (Sunday, Monday)

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