It is currently 21 Sep 2017, 12:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Find the probability that a leap year selected at random

Author Message
TAGS:

### Hide Tags

Intern
Joined: 25 Jan 2013
Posts: 24

Kudos [?]: 59 [1], given: 11

Find the probability that a leap year selected at random [#permalink]

### Show Tags

30 Jan 2013, 23:30
1
KUDOS
10
This post was
BOOKMARKED
00:00

Difficulty:

35% (medium)

Question Stats:

70% (00:51) correct 30% (01:09) wrong based on 196 sessions

### HideShow timer Statistics

Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7
[Reveal] Spoiler: OA

Last edited by Bunuel on 31 Jan 2013, 04:49, edited 2 times in total.
Renamed the topic and edited the question.

Kudos [?]: 59 [1], given: 11

Math Expert
Joined: 02 Sep 2009
Posts: 41666

Kudos [?]: 124338 [5], given: 12077

Re: Find the probability that a leap year selected at random [#permalink]

### Show Tags

31 Jan 2013, 04:48
5
KUDOS
Expert's post
6
This post was
BOOKMARKED
antoxavier wrote:
Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7

There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.

These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case.

The probability of that is 2/7.

Hope it's clear.

P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to the rule #3 (the name of a topic MUST be the first 40 characters (~the first two sentences) of the question).
_________________

Kudos [?]: 124338 [5], given: 12077

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 17586

Kudos [?]: 270 [0], given: 0

Re: Find the probability that a leap year selected at random [#permalink]

### Show Tags

25 Jul 2014, 21:19
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 270 [0], given: 0

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 17586

Kudos [?]: 270 [0], given: 0

Re: Find the probability that a leap year selected at random [#permalink]

### Show Tags

20 Jun 2016, 19:52
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 270 [0], given: 0

Manager
Joined: 01 Jun 2015
Posts: 165

Kudos [?]: 35 [0], given: 101

Location: India
GMAT 1: 620 Q48 V26

### Show Tags

21 Mar 2017, 21:14
What is the probability that a leap year selected at random will contain 53 Sundays?

A.1/7 B. 2/7 C.7/366 D.3/7 E. 52/366

Kudos [?]: 35 [0], given: 101

Math Expert
Joined: 02 Sep 2009
Posts: 41666

Kudos [?]: 124338 [0], given: 12077

Re: Find the probability that a leap year selected at random [#permalink]

### Show Tags

21 Mar 2017, 21:32
techiesam wrote:
What is the probability that a leap year selected at random will contain 53 Sundays?

A.1/7 B. 2/7 C.7/366 D.3/7 E. 52/366

Merging topics. Please refer to the solution above.
_________________

Kudos [?]: 124338 [0], given: 12077

Intern
Joined: 11 Aug 2016
Posts: 48

Kudos [?]: 7 [0], given: 0

Location: India
Concentration: Operations, General Management
Schools: HBS '18, ISB '17, IIMA
GMAT 1: 710 Q49 V38
GPA: 3.95
WE: Design (Manufacturing)
Find the probability that a leap year selected at random [#permalink]

### Show Tags

22 Mar 2017, 02:27
Any given year will always have 52 complete weeks. So 52 Sundays will always be there in any year.

A leap year has 366 days.
52 weeks = 52*7=364 days

So we have 2 extra days apart from 52 weeks.

These 2 days can be (Saturday, Sunday), (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday,Thursday), (Thursday, Friday), (Friday, Saturday).

For the year to have 53 Sundays, the 2 days must be either (Saturday, Sunday) or (Sunday, Monday)

Favourable cases = 2
Total possible cases = 7

Propability = $$\frac{Favourable}{Total}$$= $$\frac{2}{7}$$

Kudos [?]: 7 [0], given: 0

Intern
Joined: 21 Jul 2017
Posts: 45

Kudos [?]: 2 [0], given: 41

Location: India
GMAT 1: 750 Q51 V41
GPA: 4
Re: Find the probability that a leap year selected at random [#permalink]

### Show Tags

15 Sep 2017, 10:51
There are 366 days in a leap year that contain 52 weeks and 2 more days. So, 52 Sundays and 2 days.

These 2 days can be:
(Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases).

In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case.
No. of sample spaces = 7.
No. of event that gives 53rd Sunday in Leap Year = 2.

Required Probability = 2⁄7.

Hit Kudos!

Kudos [?]: 2 [0], given: 41

Re: Find the probability that a leap year selected at random   [#permalink] 15 Sep 2017, 10:51
Similar topics Replies Last post
Similar
Topics:
3 If a 3-digit integer is selected at random from the 9 02 Sep 2017, 12:12
16 When a random experiment is conducted, the probability that 12 16 Sep 2017, 06:54
11 When a random experiment is conducted, the probability that 7 28 Apr 2017, 23:58
1 if a three-digit number is selected at random 2 09 Aug 2017, 00:45
4 Tough and tricky 3: leap year 6 30 Oct 2016, 10:39
Display posts from previous: Sort by