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# Find the value of 1*1! + 2*2! + 3*3! + ......+n*n! (1)

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Find the value of 1*1! + 2*2! + 3*3! + ......+n*n! (1)  [#permalink]

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07 May 2005, 07:35
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Find the value of 1*1! + 2*2! + 3*3! + ......+n*n!

(1) n! +1
(2) (n+1)!
(3) (n+1)!-1
(4) (n+1)!+1
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Last edited by christoph on 07 May 2005, 09:50, edited 1 time in total.
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Re: PS- value [#permalink]

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07 May 2005, 09:38
christoph wrote:
Find the value of 1.1! + 2.2! + 3.3! + ......+n.n!

(1) n! +1
(2) (n+1)!
(3) (n+1)!-1
(4) (n+1)!+1

I guess you mean 1*1! + 2*2!....

if only 1 term, 1*1! = 1 ==> only (3) fits, where n in the choises is the number of terms..
if 2 terms, 1*1! + 2*2! = 5 ==> (3)

so it is (3) by backsolving.
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08 May 2005, 10:22
(3) it is...

just pick number upto 3 and see which ones add up!
08 May 2005, 10:22
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# Find the value of 1*1! + 2*2! + 3*3! + ......+n*n! (1)

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