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# Five congruent equilateral triangles are combined to form the shape

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Math Expert
Joined: 02 Sep 2009
Posts: 54375
Five congruent equilateral triangles are combined to form the shape  [#permalink]

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06 Sep 2016, 05:07
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Difficulty:

25% (medium)

Question Stats:

71% (00:57) correct 29% (01:23) wrong based on 189 sessions

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Five congruent equilateral triangles are combined to form the shape shown above. If the perimeter of this shape is 210, then what is the perimeter of one such triangle?

A. 30
B. 35
C. 42
D. 90
E. 105

Attachment:

T88923.png [ 6.16 KiB | Viewed 2169 times ]

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Five congruent equilateral triangles are combined to form the shape  [#permalink]

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06 Sep 2016, 06:51
Bunuel wrote:

Five congruent equilateral triangles are combined to form the shape shown above. If the perimeter of this shape is 210, then what is the perimeter of one such triangle?

A. 30
B. 35
C. 42
D. 90
E. 105

Attachment:
T88923.png

Took 40 secs for this...

When we have perimeter to be calculated then we need to consider only the exterior sides .

If we check then we get 7 sides for the above figure..

Let's take side be a , then 7a = 210 => a = 30.

$$Equilateral triangle perimeter is 3a$$ => 90.

IMO option D.
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Joined: 20 Sep 2011
Posts: 18
Schools: Ross '17, ISB '16, NUS '17
GMAT 1: 640 Q40 V35
Re: Five congruent equilateral triangles are combined to form the shape  [#permalink]

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06 Sep 2016, 13:32
Bunuel wrote:

Five congruent equilateral triangles are combined to form the shape shown above. If the perimeter of this shape is 210, then what is the perimeter of one such triangle?

A. 30
B. 35
C. 42
D. 90
E. 105

Attachment:
T88923.png

Ans : perimeter of 7 sides =210 => 1 side =30
since all are equilateral triangles => all sides equal => perimeter one triangle =30+30+30 =90
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Joined: 22 Nov 2016
Posts: 205
Location: United States
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Five congruent equilateral triangles are combined to form the shape  [#permalink]

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04 Jul 2017, 10:30
Perimeter is the continuous line forming the boundary of a closed geometric figure. Hence, we need to consider only 7 sides of the figure above.
The length of each side is $$\frac{210}{7} = 30$$

Hence perimeter of each triangle since equilateral is 3*30 = 90
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Five congruent equilateral triangles are combined to form the shape   [#permalink] 04 Jul 2017, 10:30
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