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Five percent of a certain grass seed is timothy. If the amount of the

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Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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20 Sep 2010, 10:10
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Five percent of a certain grass seed is timothy. If the amount of the mixture needed to plant one acre contains 2 pounds of timothy, how many acres can be planted with 240 pounds of the seed mixture?

A. 6
B. 12
C. 20
D. 24
E. 120
[Reveal] Spoiler: OA

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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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20 Sep 2010, 10:18
Five percent of a certain grass seed is timothy. If the amount of the mixture needed to plant one acre contains 2 pounds of timothy, how many acres can be planted with 240 pounds of the seed mixture?

Amount of timothy needed for one acre is 2 pounds.
So the amount of grass seed needed for one acre is
= 2 (100/5) = 40 pounds

So the no.of acres that can be planted with 240 pounds is
= 240/40 = 6

The answer is A.
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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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20 Sep 2010, 19:11
No doubt that OA has to be A
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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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14 Oct 2010, 18:23
My backwards math:

1% of 240 is 2.4 pounds
2.4+2.4+2.4+2.4+2.4=12 pounds

12pounds of timothy/2 pounds needed per acre=6 acres

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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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03 Nov 2010, 23:57
cano wrote:
Five percent of a certain grass seed is timothy. If the amount of the mixture needed to plant one acre contains 2 pounds of timothy, how many acres can be planted with 240 pounds of the seed mixture?

A. 6
B. 12
C. 20
D. 24
E. 120

Answer: A
Explanation: Let's suppose Grass Seed=G, and Timothy=T.
And, we know that 5 percent of G is T (or T is 5 percent of G)
--> $$T= \frac{5}{100} * G =\frac{1}{20} * G = \frac{G}{20}$$, and $$G= 240$$, so --> $$T = \frac{240}{20} = 12$$ pounds.

We need $$2$$ pounds of T for $$1$$ Acre
==> $$1$$ pound of T for $$\frac{1}{2}$$ Acres
==> $$12$$ pounds of T for $$12*1/2$$ Acre --> $$6$$ Acres (Answer)
So, we can plant 6 Acres with 240 pounds of seed mixture (in other words with 12 pounds of Timothy).
Hence, answer is A.

Please! do post OA (if possible).
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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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07 Nov 2010, 20:50
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cano wrote:
Five percent of a certain grass seed is timothy. If the amount of the mixture needed to plant one acre contains 2 pounds of timothy, how many acres can be planted with 240 pounds of the seed mixture?

A. 6
B. 12
C. 20
D. 24
E. 120

Timothy - 5; Total Grass seed - 100; which is same as Timothy - 1; Total Grass seed - 20;

For 1 acre; Timothy - 2; so Total Grass seed - 40 (From above)
For ? acre; Total Grass seed - 240
Since 240 is 6*40, we can plant 1*6 acres.
Answer (A).
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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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08 Nov 2010, 05:24
5% of 240 pounds is timothy which is 12 pounds. 2 pounds timothy for 1 acre land. Thus 12 pound timothy will siffuce for 6 acres.
Answer:- A

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Re: Five percent of a certain grass seed is timothy. If the amount of the [#permalink]

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13 Nov 2016, 03:42
cano wrote:
Five percent of a certain grass seed is timothy. If the amount of the mixture needed to plant one acre contains 2 pounds of timothy, how many acres can be planted with 240 pounds of the seed mixture?

A. 6
B. 12
C. 20
D. 24
E. 120

2 pounds ............5%
x pounds..............100%

x = 40 pounds for one acre thus acres = 240/40 = 6

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Re: Five percent of a certain grass seed is timothy. If the amount of the   [#permalink] 13 Nov 2016, 03:42
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