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# For a certain art exhibit, a museum sold admission tickets

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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21 Apr 2013, 01:16
SravnaTestPrep wrote:
What about this? The company sold 30 cars every 30 days. Should it be taken to mean that the company sold the cars at a particular point of time only?

Yes, although a lot of people make that grammatical mixup. The correct idiom would be "The company could sell 30 cars over 30 days" if it wasn't all 30 at once.

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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21 Apr 2013, 01:27
dave785 wrote:
SravnaTestPrep wrote:
What about this? The company sold 30 cars every 30 days. Should it be taken to mean that the company sold the cars at a particular point of time only?

Literally? Yes. The correct idiom would be "The company sold 30 cars over 30 days" if it wasn't all 30 at once.

I could also say that " the company sold 30 cars every month, starting from January and ending in December both inclusive."

I think demanding subtle language skills from the student for solving a math problem, is being unduly biased.
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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21 Apr 2013, 02:17
dave785 wrote:
I can definitely see how there might have been some confusion.

The difference between the past tense and the past perfect tense (if that's what it's called?) is that the former implies an action that happened at only one specific point in time.

It is called past continuous and it is not used in the way you seem to suggest.
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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30 Apr 2013, 15:36
it took me 16minutes and i still got it wrong. N it says 9-5:55 so why are we looking at the intervals between 9 and 9 55 only?

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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07 May 2013, 20:48
1
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I guess this is not a great question. The only thing to do is guess towards the end.

If you work with the logic that there are 11 intervals in the last hour (which is what most of us did), then you reach a total value of 3210 for the number of tickets. When you try and solve for the number of regular and student tickets, you get answers in decimals, which is not possible as the number of tickets have to be integers.

At that point, there are two options:

1) Realize that there are indeed 12 intervals in the last hour as the only other possibility.

2) Carry on with the calculation which gives an answer of something around \$28,845. As this falls between D and E, you guess on one and the probability of getting the question right is 50/50. Still better than nothing.

Although, the takeaway for this question is the keyword "inclusive". This word is more common when we deal with sets of consecutive integers or evenly spaced sets and are able to deal with it more easily there. But from now on, we will just have to pay more attention to it when we see it in other question types

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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08 May 2013, 08:56
it took me 16minutes and i still got it wrong. N it says 9-5:55 so why are we looking at the intervals between 9 and 9 55 only?

The intervals from 9 to 9:55 have been shown only to demonstrate that every hour will have 12 intervals. There are 9 such hours. So total intervals will be 12*9
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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08 Mar 2014, 03:52
hi everyone, today this question really got me confused.
and not by the "interval" nor the "inclusive" parts,

but it is the "If on one day 3 times as many regular admissions tickets were sold as student tickets" part,
my interpretation of that part means that for each regular tickets there three students tickets sold, not the other way around.
am I the only one here that got this wrong in this part?
and can someone help explain the logic in that sentence.

thanks

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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09 Mar 2014, 21:25
sayno wrote:
hi everyone, today this question really got me confused.
and not by the "interval" nor the "inclusive" parts,

but it is the "If on one day 3 times as many regular admissions tickets were sold as student tickets" part,
my interpretation of that part means that for each regular tickets there three students tickets sold, not the other way around.
am I the only one here that got this wrong in this part?
and can someone help explain the logic in that sentence.

thanks

Consider this:
You are 3 times as smart as me.

Who is smarter - you or me? You are smarter, right?

Similarly, "3 times as many regular admissions tickets were sold as student tickets"
Regular tickets sold were more or student tickets?
Regular tickets sold were 3 times so regular tickets sold were more. So there were 3 regular tickets sold for each student ticket.
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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09 Mar 2014, 22:30
Took me a little longer than I wished on this one, but here's how I came up with it:

Step 1 --> Set up the equation for total tickets sold.

Each hour has 12 intervals to sell tickets, with a total time to sell tickets of 9 hours. 9*12=108 separate intervals to sell 30 tickets, so 30*108=3,240 total tickets.

Step 2 --> Set up the equation for ticket prices.

Based on a ration of 3:1 I wanted to come up with an average ticket selling price. So I took (10+10+10+6)/4=9 because for every three adult tickets sold, we also sold one student ticket. On average the theater sold tickets for \$9.00 each.

Step 3 --> Apply the two to one another.

3,240 total tickets * \$9.00 average ticket price = \$29,160

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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28 Mar 2014, 15:57
Let us just assume that the ticket sales was done for one hour from 9.00 AM to 10. AM - both times included.
Sales happened every 5 minutes

In the above example the number of times sale happened would be 12 + 1 = 13.

Many students would forget to add the 1 at the end and hence the GMAT question setting authority had indicated that the last sale happened at 5.55 instead of at 6.00 PM.

They are really testing how quickly we can do the multiplication and splitting the total time in the ratio of 1:3 etc.

Hope this helps

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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08 May 2014, 06:54
Another way to solve is.
First intervals 60/5=12intervals per hour.
Now, from 9 to 5.55 we have 9 of such intervals hence total intervals 9*12 = 108

Then, weighted average 10\$ tx and 6\$ tx are in the ratio 3:1 hence weighted avg is 9\$.

Hence answer will be multiple of 9, (A,D are out at this point).

9*108*30=29,160.

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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04 Jul 2014, 10:35
Bunuel wrote:
clarkkent0610 wrote:
For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was \$10 and the price of a student ticket was \$6. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?

A. \$24960
B. \$25920
C. \$28080
D. \$28500
E. \$29160

From 9:00 in the morning to 5:55 in the afternoon, inclusive there are 9*12=108 five-minute intervals, thus total of 108*30 tickets were sold.

Say x student and 3x regular tickets were sold, then x+3x=108*30 --> x=27*30 and 3x=3*(27*30)=27*90.

Therefore, the total revenue from ticket sales that day was 27*30*6+27*90*10=\$29,160.

Hope it's clear.

Where did you get x = 27 * 30 from? and also 3x = 3* (27 * 30)? Are you factoring here?

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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04 Jul 2014, 10:39
sagnik2422 wrote:
Bunuel wrote:
clarkkent0610 wrote:
For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was \$10 and the price of a student ticket was \$6. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?

A. \$24960
B. \$25920
C. \$28080
D. \$28500
E. \$29160

From 9:00 in the morning to 5:55 in the afternoon, inclusive there are 9*12=108 five-minute intervals, thus total of 108*30 tickets were sold.

Say x student and 3x regular tickets were sold, then x+3x=108*30 --> x=27*30 and 3x=3*(27*30)=27*90.

Therefore, the total revenue from ticket sales that day was 27*30*6+27*90*10=\$29,160.

Hope it's clear.

Where did you get x = 27 * 30 from? and also 3x = 3* (27 * 30)? Are you factoring here?

x+3x=108*30 --> 4x=108*30 --> reduce by 4: x=27*30 --> multiply by 3: 3x=3*(27*30)=27*90.

I think you need to brush up fundamentals...
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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04 Jul 2014, 12:03
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Bunuel wrote:
carcass wrote:
Sorry Bunuel but our statement say: 9 Am to 5.55 PM so we have 12*8 = 96 + 11 (and not 12 because the museum sells tickets untill 5.55 PM) so = 107

Thi poin is still unclear for me.

From 9:00 in the morning to 5:55 in the afternoon, inclusive there are are 9*12=108 five-minute intervals, the same way as from 9:00 to 9:55 there are 12 five-minute intervals:
9:00
9:05
9:10
9:15
9:20
9:25
9:30
9:35
9:40
9:45
9:50
9:55

Hope it's clear.

Hi Bunuel,
Can you help me in clarifying the number of 5 min intervals we have from 9:00 to 5:55 ?
I am getting 107 intervals and not 108
from 9:00(am)to 5:00(pm) we have 8*12=96 intervals
from 5:05 to 5:55 we have 11 intervals
so a total of 96+11 = 107 intervals and not 108 intervals. where's the trick I am falling for ?
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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08 Jul 2014, 07:51
Bunuel wrote:
clarkkent0610 wrote:
For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was \$10 and the price of a student ticket was \$6. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?

A. \$24960
B. \$25920
C. \$28080
D. \$28500
E. \$29160

From 9:00 in the morning to 5:55 in the afternoon, inclusive there are 9*12=108 five-minute intervals, thus total of 108*30 tickets were sold.

Say x student and 3x regular tickets were sold, then x+3x=108*30 --> x=27*30 and 3x=3*(27*30)=27*90.

Therefore, the total revenue from ticket sales that day was 27*30*6+27*90*10=\$29,160.

Hope it's clear.

Why are we multiplying by 9?

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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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08 Jul 2014, 23:35
sagnik242 wrote:
Bunuel wrote:
clarkkent0610 wrote:
For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was \$10 and the price of a student ticket was \$6. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?

A. \$24960
B. \$25920
C. \$28080
D. \$28500
E. \$29160

From 9:00 in the morning to 5:55 in the afternoon, inclusive there are 9*12=108 five-minute intervals, thus total of 108*30 tickets were sold.

Say x student and 3x regular tickets were sold, then x+3x=108*30 --> x=27*30 and 3x=3*(27*30)=27*90.

Therefore, the total revenue from ticket sales that day was 27*30*6+27*90*10=\$29,160.

Hope it's clear.

Why are we multiplying by 9?

Because there are 9 hours:
9 to 10 am
10 to 11 am
11 to 12 noon
12 to 1 pm
1 to 2 pm
2 to 3 pm
3 to 4 pm
4 to 5 pm
5 to 6 pm

In each hour there are 12 intervals.
9:00 to 9:05 am
9:05 to 9:10 am
and so on...

Hence 9*12
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Re: For a certain art exhibit, a museum sold admission tickets [#permalink]

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09 Jul 2014, 07:53
Thanks, actually now I am confused how x+3x = 108*30 goes to x=27*30 and 3x=3*(27*30)=27*90.

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21 Aug 2015, 22:59
I got confused with the statement "3 times as many regular admission tickets were sold as student tickets".
I incorrectly considered S = 3R, where S is no. of student's ticket and R is no. of regular ticket.
Bunuel, is there any trick to take care of statements like "twice as many as" "thrice as many as"?

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22 Nov 2015, 23:58
this 5 minute stuff also confused me, anyway I went on solving with 107*30, the number when divided by 4 was not going to be an integer value I understood so my results should then be adjusted UP.

i calculated to the following point: 28 890 total rev - so choice E without much of moral suffering because I know I have screwed up smth, I also know I have little time and know that the figure should be actually a bit bigger, rather than smaller
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