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For a certain car repair, the total charge consisted of a charge for p

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For a certain car repair, the total charge consisted of a charge for p  [#permalink]

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New post 21 Oct 2015, 21:39
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For a certain car repair, the total charge consisted of a charge for parts, a charge for labor, and a 6 percent sales tax on both the charge for parts and the charge for labor. If the charge for parts, excluding sales tax, was $50.00, what was the total charge for the repair?

(1) The sales tax on the charge for labor was $9.60.
(2) The total sales tax was $12.60.


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Re: For a certain car repair, the total charge consisted of a charge for p  [#permalink]

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New post 21 Oct 2015, 22:58
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Let total charge for repair= T
Charge for parts excluding sales tax, P=50
Let charge for labour excluding sales tax = L

T=1.06 *(50+L)
= 53 +1.06L

1.
.06L=9.60
=>L = 160
Sufficient

2.
.06*(50+L)=12.6
=>3+.06L =12.6
=>.06L=9.60
Sufficient
Answer D
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Re: For a certain car repair, the total charge consisted of a charge for p  [#permalink]

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New post 21 Oct 2015, 23:28
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P = Charge for parts = 50$
L = Charge for labor
T = Total Cost

T = P + L + (0.06)P + (0.06)L

St1: 0.06L = 9.6 --> L = 9.6/0.06 --> Sufficient
St2: 0.06P + 0.06L = 12.16 --> We get the value of L --> Sufficient

Answer: D
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For a certain car repair, the total charge consisted of a charge for p  [#permalink]

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New post 23 Oct 2015, 00:57
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Bunuel wrote:
For a certain car repair, the total charge consisted of a charge for parts, a charge for labor, and a 6 percent sales tax on both the charge for parts and the charge for labor. If the charge for parts, excluding sales tax, was $50.00, what was the total charge for the repair?

(1) The sales tax on the charge for labor was $9.60.
(2) The total sales tax was $12.60.


Kudos for a correct solution.


Set up the equation. Let the charge for parts be P and the charge for labor be L. The question asks:

Total = P + L + 0.06P + 0.06L = ?
Total = 50 + L + 0.06*50 + 0.06L = ? (P is already given)

1) Gives you the value for L, hence sufficient
2) 12.60 = 0.06*50+0.06L, from this you can calculate the Value for L and hence the total too

Answer D
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Re: For a certain car repair, the total charge consisted of a charge for p  [#permalink]

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New post 19 Aug 2016, 06:42
Vyshak wrote:
P = Charge for parts = 50$
L = Charge for labor
T = Total Cost

T = P + L + (0.06)P + (0.06)L

St1: 0.06L = 9.6 --> L = 9.6/0.06 --> Sufficient
St2: 0.06P + 0.06L = 12.16 --> We get the value of L --> Sufficient

Answer: D

Quote:
Sir:
while the question is straight forward.
How can you be sure that the sales tax on charge labor is 6%.
In the question stem, it is given 6 percent sales tax on both charge for parts and charge for labor.
Individually, the sales tax can vary for charge part Vs. charge for labor.

Or by default, the sales tax even if mentioned for both the items, it never varies for individual items?

Please share your thoughts.
Thanks in advance.

Regards,
Yosita

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Re: For a certain car repair, the total charge consisted of a charge for p  [#permalink]

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New post 18 Sep 2017, 04:55
P=$50, Charge = L + P + 6/100(L+P)
1. 6/100*L=$9.6 L can be found out so, Sufficient
2. 6%(L+P)=$12.6 P can be calculated so sufficient
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Re: For a certain car repair, the total charge consisted  [#permalink]

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Re: For a certain car repair, the total charge consisted   [#permalink] 03 May 2019, 04:24
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