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# For a finite sequence of non zero numbers, the number of

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Senior Manager
Joined: 02 Sep 2006
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For a finite sequence of non zero numbers, the number of [#permalink]

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02 Apr 2007, 01:41
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For a finite sequence of non zero numbers, the number of variations in signs is defined as the number of pairs of consecutive terms for which the product of the two consecutive terms is negative. What is the number of varations for the number in sequence 1,-3, 2,5,-4,-6?

a)1
b)2
c)3
d)4
e)5

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Senior Manager
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05 Apr 2007, 21:30

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06 Apr 2007, 16:32
the question asks if you multiply each term in the series with the next term, how many such products will be negative ?

so let us multipy the first term byu the second term: 1 * -3 = -3 (negative)
2nd term * 3rd term = -3 * 2 = -6 (negative)

3rd term * 4th term = 2*5 = 10 (positive)
4th term * 5th term = 5* -4 = -20 (negative)
5th term * 6th term = -4*-6 = 24 (positive)

total = 3 negatives. therefore, C

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Senior Manager
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06 Apr 2007, 17:27
Thanks qxjmba!

Sometimes, it is difficult for me to understand the question stem. You people are wonderful! Always helping

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Manager
Joined: 28 Feb 2007
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Location: California
Re: PS: finite consecutive terms [#permalink]

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06 Apr 2007, 20:28
faifai0714 wrote:
For a finite sequence of non zero numbers, the number of variations in signs is defined as the number of pairs of consecutive terms for which the product of the two consecutive terms is negative. What is the number of varations for the number in sequence 1,-3, 2,5,-4,-6?

a)1
b)2
c)3
d)4
e)5

1 x -3 is negative
-3 x 2 is negative
2 x 5 is positive
5 x -4 is negative
-4 x -6 is positive

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Senior Manager
Joined: 02 Sep 2006
Posts: 253

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10 Apr 2007, 05:41
Summer3 wrote:
Thanks qxjmba!

Sometimes, it is difficult for me to understand the question stem. You people are wonderful! Always helping

I also didn't understand the question before...thanks!!!!

Kudos [?]: 75 [0], given: 0

10 Apr 2007, 05:41
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