It is currently 23 Oct 2017, 01:15

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# For a finite sequence of nonzero numbers, the number of

Author Message
Director
Joined: 10 Feb 2006
Posts: 660

Kudos [?]: 625 [0], given: 0

For a finite sequence of nonzero numbers, the number of [#permalink]

### Show Tags

17 May 2007, 07:05
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?

One
Two
Three
Four
Five
_________________

GMAT the final frontie!!!.

Kudos [?]: 625 [0], given: 0

Manager
Joined: 02 May 2007
Posts: 152

Kudos [?]: 5 [0], given: 0

### Show Tags

17 May 2007, 08:15
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?

One
Two
Three
Four
Five

Three variations

(1,-3), (-3,2) and (5,-4)

Kudos [?]: 5 [0], given: 0

Senior Manager
Joined: 03 May 2007
Posts: 270

Kudos [?]: 14 [0], given: 0

### Show Tags

17 May 2007, 08:45
kirakira wrote:
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?

One
Two
Three
Four
Five

Three variations

(1,-3), (-3,2) and (5,-4)

can you explain how you did it?

Kudos [?]: 14 [0], given: 0

Manager
Joined: 30 Mar 2007
Posts: 213

Kudos [?]: 11 [0], given: 0

### Show Tags

17 May 2007, 12:26
the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative

1,-3,2,5,-4,-6

(1,-3), (-3,2) and (5,-4)

will give the product as -iv.

so no. of variations is 3.

Kudos [?]: 11 [0], given: 0

Director
Joined: 10 Feb 2006
Posts: 660

Kudos [?]: 625 [0], given: 0

### Show Tags

18 May 2007, 05:47
"number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative "

I don't see two consecutive terms, care to explain further please. Thanks
_________________

GMAT the final frontie!!!.

Kudos [?]: 625 [0], given: 0

18 May 2007, 05:47
Display posts from previous: Sort by