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# For all integers n n = n*(n-1). What is the value of x ? 1 x

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Manager
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For all integers n n = n*(n-1). What is the value of x ? 1 x [#permalink]

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12 Sep 2005, 09:58
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For all integers n nÂ°= n*(n-1). What is the value of xÂ°?

1 xÂ°=x
2 (x-1)Â°=x-2

please...indicate how long it took you to work it out..grazie=)
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12 Sep 2005, 10:05
D it is...

x=2

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VP
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12 Sep 2005, 10:20
B.
I messed up in algebra.

Given: n0 = n * (n - 1) ------ (a)

i)
x0 = x
from (a), substitute value od x0:
x* (x - 1) = x

As x can be 0 (its integer), we cannot divide this equation. Simplifying:
x ^ 2 - x = x
x ^ 2 - 2 x = 0
we cannot solve this for x, and therefore cannot compute x0.

ii) (x - 1)0 = x - 2
from (a)
(x - 1) ( x - 2) = (x - 2)

x^2 - 4x + 4 = 0

or x = 2.

Last edited by duttsit on 12 Sep 2005, 10:55, edited 1 time in total.

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Manager
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12 Sep 2005, 10:32

i go with (b)

statement I: x(x-1)=x
x^2-2x=0
x(x-2)=0

x = 0 or x=2... insufficient.

statement II: (x-1)(x-2)=x-2
instead of opening it out, we can tell that x-1=1 or x = 2, thus, sufficient.

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Senior Manager
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12 Sep 2005, 11:45
B) chets method.
Less than a minute.
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13 Sep 2005, 08:26
OA i s b..thanks everyone
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13 Sep 2005, 08:26
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