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For all numbers s and t, the operation * is defined by s*t =

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For all numbers s and t, the operation * is defined by s*t = [#permalink]

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The Official Guide For GMAT® Quantitative Review, 2ND Edition

For all numbers s and t, the operation * is defined by s*t = (s - 1)(t + 1). If (-2)*x = -12, then x =

(A) 2
(B) 3
(C) 5
(D) 6
(E) 11

Problem Solving
Question: 113
Category:Algebra First-degree equations
Page: 76
Difficulty: 600


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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 24 Feb 2014, 22:59
SOLUTION

For all numbers s and t, the operation * is defined by s*t = (s - 1)(t + 1). If (-2)*x = -12, then x =

(A) 2
(B) 3
(C) 5
(D) 6
(E) 11

Since \(s*t = (s - 1)(t + 1)\), then \((-2)*x = (-2-1)(x+1)=-3(x+1)\).

So, we are given that \(-3(x+1)=-12\) --> \(x+1=4\) -> \(x=3\).

Answer: B.
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Collection of Questions:
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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 25 Feb 2014, 04:02
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(-2)^*X= -12

= (-2-1) (X+1)= -12
x= 3

B?
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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 26 Feb 2014, 01:13
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Option B.
(-2)*x=-12
(-2-1)(x+1)=-12
x+1=4
x=3

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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 01 Mar 2014, 03:19
SOLUTION

For all numbers s and t, the operation * is defined by s*t = (s - 1)(t + 1). If (-2)*x = -12, then x =

(A) 2
(B) 3
(C) 5
(D) 6
(E) 11

Since \(s*t = (s - 1)(t + 1)\), then \((-2)*x = (-2-1)(x+1)=-3(x+1)\).

So, we are given that \(-3(x+1)=-12\) --> \(x+1=4\) -> \(x=3\).

Answer: B.
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For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 03 Mar 2015, 13:38
Can I please get an explaination to this? Completely clueless..

How do you conclude that s = -2 and t = x?

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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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Hi erikvm,

This is an example of a "Symbolism" question (you'll likely see one of them on Test Day). The basic concept is usually pretty simple - the prompt will "make up' a math symbol, explain to you what it "means" mathematically, then ask you to use it to perform a calculation.

Since the * symbol makes people think about multiplication, I'm going to change it to a # symbol. Here, we're told....

S#T = (S-1)(T+1)

You are meant to take the numbers that S and T represent and place them into the calculation. So, as an example, if we had...

2#3 then that would equal (2-1)(3+1) = (1)(4) = 4

Knowing that, we're given....

(-2)#X = -12 and we're asked to solve for X

Let's 'substitute in' the (-2) and the X....

(-2 - 1)(X + 1) = -12

Now, you can do the algebra....
(-3)(X + 1) = -12
(X + 1) = 4
X = 3

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[Reveal] Spoiler:
B


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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 04 Mar 2015, 02:16
erikvm wrote:
Can I please get an explaination to this? Completely clueless..

How do you conclude that s = -2 and t = x?


Check other function questions in our Special Questions Directory:

Operations/functions defining algebraic/arithmetic expressions
Symbols Representing Arithmetic Operation
Rounding Functions
Various Functions
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Collection of Questions:
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Re: For all numbers s and t, the operation * is defined by s*t = [#permalink]

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New post 25 Aug 2017, 10:06
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

For all numbers s and t, the operation * is defined by s*t = (s - 1)(t + 1). If (-2)*x = -12, then x =

(A) 2
(B) 3
(C) 5
(D) 6
(E) 11



We are given that s * t = (s - 1)(t + 1).

Since (-2) * x = -12:

(-2 - 1)(x + 1) = -12

(-3)(x + 1) = -12

-3x - 3 = -12

-3x = -9

x = 3

Answer: B
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Re: For all numbers s and t, the operation * is defined by s*t =   [#permalink] 25 Aug 2017, 10:06
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