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For all numbers x and y, the function x#y = (x+2)(y-1). What is the

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For all numbers x and y, the function x#y = (x+2)(y-1). What is the  [#permalink]

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New post 19 Sep 2018, 00:45
2
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

83% (01:03) correct 17% (01:02) wrong based on 20 sessions

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For all numbers x and y, the function x#y = (x+2)(y-1). What is the value of 2#[3#(-1#1)]?

A. -44
B. -24
D. 0
C. 16
E. 28

Source: Experts Global

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Re: For all numbers x and y, the function x#y = (x+2)(y-1). What is the  [#permalink]

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New post 19 Sep 2018, 00:52
2#[3#(-1#1)]

-1#1 = (-1+2)(1-1) = 0

3#0 = (3+2)(0-1) = -5

2#-5 = (2+2)(-5-1) = 4*-6 = -24

B is the answer.
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Re: For all numbers x and y, the function x#y = (x+2)(y-1). What is the   [#permalink] 19 Sep 2018, 00:52
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For all numbers x and y, the function x#y = (x+2)(y-1). What is the

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