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For all numbers x and y, the operation & is defined by x&y

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For all numbers x and y, the operation & is defined by x&y  [#permalink]

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New post 27 Aug 2018, 09:32
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

93% (00:49) correct 7% (01:28) wrong based on 29 sessions

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For all numbers x and y, the operation & is defined by x&y  [#permalink]

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New post 27 Aug 2018, 12:22
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1
carcass wrote:
For all numbers x and y, the operation & is defined by \(x&y = \frac{x-y}{x-1}\) . If \((-3)&q=2\), then q =

A. -11

B. -8

C. -5

D. 5

E. 11


Since \(x&y = \frac{x-y}{x-1}\), similarly we can write
\((-3)&q\)=\(\frac{-3-q}{-3-1}\)=\(\frac{-3-q}{-4}\)
Given, \((-3)&q=2\)
Or, \(\frac{-3-q}{-4}=2\)
Cross-multiplying, we have
-3-q=-8
Or, q=-3+8=5

Ans. (D)
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For all numbers x and y, the operation & is defined by x&y &nbs [#permalink] 27 Aug 2018, 12:22
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