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Math Expert V
Joined: 02 Sep 2009
Posts: 57996
For all positive numbers x, Δx is defined as the cube root of x, and ∇  [#permalink]

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Difficulty:   15% (low)

Question Stats: 80% (01:26) correct 20% (01:54) wrong based on 69 sessions

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For all positive numbers x, Δx is defined as the cube root of x, and ∇x is defined as the square root of x. If ∇(Δk)=m^2 , then k =

A. m^(12/5)

B. m^6

C. m^12

D. m^36

E. m^64

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Senior PS Moderator V
Joined: 26 Feb 2016
Posts: 3352
Location: India
GPA: 3.12
For all positive numbers x, Δx is defined as the cube root of x, and ∇  [#permalink]

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Bunuel wrote:
For all positive numbers x, Δx is defined as the cube root of x, and ∇x is defined as the square root of x. If ∇(Δk)=m^2 , then k =

A. m^(12/5)

B. m^6

C. m^12

D. m^36

E. m^64

Best way to go about doing this problem is to substitute a value for $$m$$. Let $$m = 2$$

Therefore, we have to find the value of ∇(Δk) = $$m^2$$ or 4

$$4(2^2)$$ is the cube root of $$4*4*4 = 64(2^6)$$, which the square root of $$64*64 = 4096(2^{12})$$

Substituting the values in the answer options, we arrive at the value of k which is $$m^{12}$$ (Option C)
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For all positive numbers x, Δx is defined as the cube root of x, and ∇  [#permalink]

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1
Bunuel wrote:
For all positive numbers x, Δx is defined as the cube root of x, and ∇x is defined as the square root of x. If ∇(Δk)=m^2 , then k =

A. m^(12/5)

B. m^6

C. m^12

D. m^36

E. m^64

$$∇(Δk)=m^2$$
Or,$$∇(k^{\frac{1}{3}})=m^2$$
Or, $$(k^{\frac{1}{3}})^{\frac{1}{2}}=m^2$$
Or, $$k^{\frac{1}{2}*\frac{1}{3}}=m^2$$
Or, $$k^{\frac{1}{6}}=m^2$$
Or,$$k=(m^2)^6=m^{12}$$

Ans. (C)
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Rise above the storm, you will find the sunshine For all positive numbers x, Δx is defined as the cube root of x, and ∇   [#permalink] 22 Aug 2018, 04:23
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# For all positive numbers x, Δx is defined as the cube root of x, and ∇

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